Created
March 18, 2011 09:03
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Time performance: `a.prod()` vs. `reduce(lambda x,y:x*y, a)`
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In [1]: import numpy as np | |
In [2]: a = np.r_[.1:4:40j] | |
In [3]: a | |
Out[3]: | |
array([ 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1. , 1.1, | |
1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2. , 2.1, 2.2, | |
2.3, 2.4, 2.5, 2.6, 2.7, 2.8, 2.9, 3. , 3.1, 3.2, 3.3, | |
3.4, 3.5, 3.6, 3.7, 3.8, 3.9, 4. ]) | |
In [4]: timeit reduce(lambda x,y:x*y, a) | |
100000 loops, best of 3: 18.1 us per loop | |
In [5]: timeit a.prod() | |
1000000 loops, best of 3: 1.88 us per loop | |
In [6]: reduce(lambda x,y:x*y, a) | |
Out[6]: 81591528.324789688 | |
In [7]: a.prod() | |
Out[7]: 81591528.324789688 | |
In [8]: timeit np.prod(a) | |
100000 loops, best of 3: 2.4 us per loop | |
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