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byte[] hexStringToByteArray(String s) { | |
int len = s.length(); | |
byte[] data = new byte[len / 2]; | |
for (int i = 0; i < len; i += 2) { | |
data[i / 2] = (byte) ((Character.digit(s.charAt(i), 16) << 4) | |
+ Character.digit(s.charAt(i+1), 16)); | |
} | |
return data; | |
} | |
char[] hexArray = "0123456789ABCDEF".toCharArray(); | |
String bytesToHex(byte[] bytes) { | |
char[] hexChars = new char[bytes.length * 2]; | |
for ( int j = 0; j < bytes.length; j++ ) { | |
int v = bytes[j] & 0xFF; | |
hexChars[j * 2] = hexArray[v >>> 4]; | |
hexChars[j * 2 + 1] = hexArray[v & 0x0F]; | |
} | |
return new String(hexChars); | |
} | |
// Using this will remove the leading zeros, | |
String result = new BigInteger(1, inputBytes).toString(16); | |
// Edit: Not safe for leading zeros, as noted by the poster. | |
new BigInteger("00A0BF", 16).toByteArray(); |
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