Created
March 18, 2014 06:26
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Max Points on a Line [LeetCode]
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/** | |
* Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. | |
*/ | |
import java.util.Map; | |
import java.util.HashMap; | |
import java.util.Set; | |
public class MaxPointsOnALine { | |
public static int maxPoints(Point[] points) { | |
if(points.length < 2) return points.length; | |
int pointCount = points.length; | |
int globalMaxCount = 1; | |
Map<Double, Integer> hm = new HashMap<Double, Integer>(); | |
for(int i = 0; i < pointCount; i++){ | |
hm.clear(); | |
int samePointCount = 0; | |
double slope; | |
int maxCount = 0; | |
for(int j = i + 1; j < pointCount; j++){ | |
if(points[i].x == points[j].x && points[i].y == points[j].y){ | |
samePointCount++; | |
continue; | |
} else if(points[i].x == points[j].x && points[i].y != points[j].y){ | |
slope = Double.MAX_VALUE; | |
} else if(points[i].y == points[j].y){ | |
slope = 0; | |
} else { | |
slope = (double)(points[i].y - points[j].y) / (double)(points[i].x - points[j].x); | |
} | |
if(hm.containsKey(slope)){ | |
int tmp = hm.get(slope) + 1; | |
hm.put(slope, tmp); | |
if(tmp > maxCount) maxCount = tmp; | |
} else { | |
hm.put(slope, 1); | |
if(maxCount == 0) maxCount = 1; | |
} | |
} // end inside for loop | |
if(globalMaxCount < maxCount + samePointCount + 1) globalMaxCount = maxCount + samePointCount + 1; | |
} // end outside for loop | |
return globalMaxCount; | |
} | |
public static void main(String[] args){ | |
Point[] p = new Point[]{new Point(2,3),new Point(3,3),new Point(-5,3) }; | |
System.out.println(maxPoints(p)); | |
} | |
} | |
class Point { | |
int x; | |
int y; | |
Point() { x = 0; y = 0; } | |
Point(int a, int b) { x = a; y = b; } | |
} |
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