A faster, "complete" Java HttpServletRequest.getRequestUrl() replacement

GetRequestUrl.java

import javax.servlet.http.HttpServletRequest;

public class GetRequestUrl{
	/**
	 * <p>A faster replacement for {@link HttpServletRequest#getRequestURL()}
	 * 	(returns a {@link String} instead of a {@link StringBuffer} - and internally uses a {@link StringBuilder})
	 * 	that also includes the {@linkplain HttpServletRequest#getQueryString() query string}.</p>
	 * <p><a href="https://gist.github.com/ziesemer/700376d8da8c60585438"
	 * 	>https://gist.github.com/ziesemer/700376d8da8c60585438</a></p>
	 * @author Mark A. Ziesemer
	 * 	<a href="http://www.ziesemer.com.">&lt;www.ziesemer.com&gt;</a>
	 */
	public String getRequestUrl(final HttpServletRequest req){
		final String scheme = req.getScheme();
		final int port = req.getServerPort();
		final StringBuilder url = new StringBuilder(256);
		url.append(scheme);
		url.append("://");
		url.append(req.getServerName());
		if(!(("http".equals(scheme) && (port == 0 || port == 80))
				|| ("https".equals(scheme) && port == 443))){
			url.append(':');
			url.append(port);
		}
		url.append(req.getRequestURI());
		final String qs = req.getQueryString();
		if(qs != null){
			url.append('?');
			url.append(qs);
		}
		final String result = url.toString();
		return result;
	}
}

See also:

• http://blogger.ziesemer.com/2017/08/httpservletrequestgetrequesturl.html
• https://stackoverflow.com/questions/2222238/httpservletrequest-to-complete-url