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@zyan0
Created June 14, 2013 04:09
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Cubing Numbers Using CUDA
#include <stdio.h>
__global__ void cube(float * d_out, float * d_in){
int idx = threadIdx.x;
float f = d_in[idx];
d_out[idx] = f * f * f;
}
int main(int argc, char ** argv) {
const int ARRAY_SIZE = 64;
const int ARRAY_BYTES = ARRAY_SIZE * sizeof(float);
// generate the input array on the host
float h_in[ARRAY_SIZE];
for (int i = 0; i < ARRAY_SIZE; i++) {
h_in[i] = float(i);
}
float h_out[ARRAY_SIZE];
// declare GPU memory pointers
float * d_in;
float * d_out;
// allocate GPU memory
cudaMalloc((void**) &d_in, ARRAY_BYTES);
cudaMalloc((void**) &d_out, ARRAY_BYTES);
// transfer the array to the GPU
cudaMemcpy(d_in, h_in, ARRAY_BYTES, cudaMemcpyHostToDevice);
// launch the kernel
cube<<<1, ARRAY_SIZE>>>(d_out, d_in);
// copy back the result array to the CPU
cudaMemcpy(h_out, d_out, ARRAY_BYTES, cudaMemcpyDeviceToHost);
// print out the resulting array
for (int i =0; i < ARRAY_SIZE; i++) {
printf("%f", h_out[i]);
printf(((i % 4) != 3) ? "\t" : "\n");
}
cudaFree(d_in);
cudaFree(d_out);
return 0;
}
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