remove a path from the $PATH in Bash

fgrep.sh

# this will leave trailing :
removeFromPath() {
    PATH=$(echo -n $PATH | tr ":" "\n" | fgrep -vx "$1" | tr "\n" ":")
}

fgrep2.sh

removeFromPath() {
  local NEWPATH
  NEWPATH=$(echo "${PATH//:/$'\n'}" | fgrep -vx "/usr/bin")
  NEWPATH=$(echo "${NEWPATH//$'\n'/:}")
  PATH=$NEWPATH
}

perl.sh

removeFromPath() {
    local REMDIR="$1"
    local NEWPATH=$(echo :$PATH: | perl -pe "
        s|:\\Q${REMDIR}:||g;
        s/^:|:$//g;
    ")
    echo $NEWPATH
}

pureBash.sh

# does not work with *
removeFromPath() {
    # https://stackoverflow.com/questions/370047/what-is-the-most-elegant-way-to-remove-a-path-from-the-path-variable-in-bash#2108540
    local REMOVE WORK
    REMOVE=":$1:"
    WORK=":$PATH:"
    WORK=${WORK//$REMOVE/:}
    WORK=${WORK/#:/}
    WORK=${WORK/%:/}
    PATH=$WORK
}