Tip to generate random password in Kotlin

gistfile1.txt

fun generateRandomPassword(): String {
    val chars = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
    var passWord = ""
    for (i in 0..31) {
        passWord += chars[Math.floor(Math.random() * chars.length).toInt()]
    }
    return passWord
}

Since Kotlin 1.3 you can use Random.nextInt(0, chars.length) instead of Math.floor(Math.random() * chars.length).toInt().

        private val STRING_CHARACTERS = ('0'..'z').toList().toTypedArray()
        val password = (1..32).map { STRING_CHARACTERS.random() }.joinToString("")

just stumbled over this, I'm not saying that thats how you should ever create a password. just wanted to show a simpler way

private val chars = ('a'..'Z') + ('A'..'Z') + ('0'..'9')
private fun randomID(): String = List(16) { chars.random() }.joinToString("")

private val chars = ('a'..'Z') + ('A'..'Z') + ('0'..'9')
private fun randomID(): String = List(16) { chars.random() }.joinToString("")

This worked for me.

// Could be this way for a length of 8 password with visible ascii characters
var password = List(8){(0x21..0x7e).random().toChar()}.joinToString("")