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@Audhil
Created June 11, 2017 18:57
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Tip to generate random password in Kotlin
fun generateRandomPassword(): String {
val chars = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
var passWord = ""
for (i in 0..31) {
passWord += chars[Math.floor(Math.random() * chars.length).toInt()]
}
return passWord
}
@christophsturm
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        private val STRING_CHARACTERS = ('0'..'z').toList().toTypedArray()
        val password = (1..32).map { STRING_CHARACTERS.random() }.joinToString("")

@christophsturm
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just stumbled over this, I'm not saying that thats how you should ever create a password. just wanted to show a simpler way

@LarsArtmann
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private val chars = ('a'..'Z') + ('A'..'Z') + ('0'..'9')
private fun randomID(): String = List(16) { chars.random() }.joinToString("")

@lawloretienne
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private val chars = ('a'..'Z') + ('A'..'Z') + ('0'..'9')
private fun randomID(): String = List(16) { chars.random() }.joinToString("")

This worked for me.

@nancwang
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// Could be this way for a length of 8 password with visible ascii characters
var password = List(8){(0x21..0x7e).random().toChar()}.joinToString("")

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