Skip to content

Instantly share code, notes, and snippets.

What would you like to do?
resolve the problem on Python 3.x
#!/usr/bin/env python
# Converts any integer into a base [BASE] number. I have chosen 62
# as it is meant to represent the integers using all the alphanumeric
# characters, [no special characters] = {0..9}, {A..Z}, {a..z}
# I plan on using this to shorten the representation of possibly long ids,
# a la url shortenters
# saturate() takes the base 62 key, as a string, and turns it back into an integer
# dehydrate() takes an integer and turns it into the base 62 string
import math
import sys
BASE = 62
def true_ord(char):
Turns a digit [char] in character representation
from the number system with base [BASE] into an integer.
if char.isdigit():
return ord(char) - DIGIT_OFFSET
elif 'A' <= char <= 'Z':
return ord(char) - UPPERCASE_OFFSET
elif 'a' <= char <= 'z':
return ord(char) - LOWERCASE_OFFSET
raise ValueError("%s is not a valid character" % char)
def true_chr(integer):
Turns an integer [integer] into digit in base [BASE]
as a character representation.
if integer < 10:
return chr(integer + DIGIT_OFFSET)
elif 10 <= integer <= 35:
return chr(integer + UPPERCASE_OFFSET)
elif 36 <= integer < 62:
return chr(integer + LOWERCASE_OFFSET)
raise ValueError("%d is not a valid integer in the range of base %d" % (integer, BASE))
def saturate(key):
Turn the base [BASE] number [key] into an integer
int_sum = 0
reversed_key = key[::-1]
for idx, char in enumerate(reversed_key):
int_sum += true_ord(char) * int(math.pow(BASE, idx))
return int_sum
def dehydrate(integer):
Turn an integer [integer] into a base [BASE] number
in string representation
# we won't step into the while if integer is 0
# so we just solve for that case here
if integer == 0:
return '0'
string = ""
while integer > 0:
remainder = integer % BASE
string = true_chr(remainder) + string
integer =int(integer/BASE)
return string
if __name__ == '__main__':
# not really unit tests just a rough check to see if anything is way off
if sys.argv[1] == '-tests':
passed_tests = True
for i in xrange(0, 1000):
passed_tests &= (i == saturate(dehydrate(i)))
print (passed_tests)
user_input = sys.argv[2]
if sys.argv[1] == '-s':
print (saturate(user_input))
elif sys.argv[1] == '-d':
print (dehydrate(int(user_input)))
print ("I don't understand option %s" % sys.argv[1])
except ValueError as e:
print (e)

This comment has been minimized.

Copy link
Owner Author

@Biglucky Biglucky commented Jan 27, 2019


This comment has been minimized.

Copy link

@euclidr euclidr commented May 27, 2019

hey, I found a problem in this gist, in dehydrate function, if integer is very big the result will be wrong, because the division result is float type which can't represent every integer above 2^53.

In L80 we should use double slash // instead of /.

>>> mu64 = 18446744073709551615
>>> mu64 / 62 % 62
>>> (mu64 // 62) % 62
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
You can’t perform that action at this time.