Skip to content

Instantly share code, notes, and snippets.

@Biglucky
Forked from bhelx/base_62_converter.py
Last active October 11, 2023 03:55
Show Gist options
  • Star 2 You must be signed in to star a gist
  • Fork 1 You must be signed in to fork a gist
  • Save Biglucky/da106aabab769cf25396262eb72783db to your computer and use it in GitHub Desktop.
Save Biglucky/da106aabab769cf25396262eb72783db to your computer and use it in GitHub Desktop.
resolve the problem on Python 3.x
#!/usr/bin/env python
#
# Converts any integer into a base [BASE] number. I have chosen 62
# as it is meant to represent the integers using all the alphanumeric
# characters, [no special characters] = {0..9}, {A..Z}, {a..z}
#
# I plan on using this to shorten the representation of possibly long ids,
# a la url shortenters
#
# saturate() takes the base 62 key, as a string, and turns it back into an integer
# dehydrate() takes an integer and turns it into the base 62 string
#
import math
import sys
BASE = 62
UPPERCASE_OFFSET = 55
LOWERCASE_OFFSET = 61
DIGIT_OFFSET = 48
def true_ord(char):
"""
Turns a digit [char] in character representation
from the number system with base [BASE] into an integer.
"""
if char.isdigit():
return ord(char) - DIGIT_OFFSET
elif 'A' <= char <= 'Z':
return ord(char) - UPPERCASE_OFFSET
elif 'a' <= char <= 'z':
return ord(char) - LOWERCASE_OFFSET
else:
raise ValueError("%s is not a valid character" % char)
def true_chr(integer):
"""
Turns an integer [integer] into digit in base [BASE]
as a character representation.
"""
if integer < 10:
return chr(integer + DIGIT_OFFSET)
elif 10 <= integer <= 35:
return chr(integer + UPPERCASE_OFFSET)
elif 36 <= integer < 62:
return chr(integer + LOWERCASE_OFFSET)
else:
raise ValueError("%d is not a valid integer in the range of base %d" % (integer, BASE))
def saturate(key):
"""
Turn the base [BASE] number [key] into an integer
"""
int_sum = 0
reversed_key = key[::-1]
for idx, char in enumerate(reversed_key):
int_sum += true_ord(char) * int(math.pow(BASE, idx))
return int_sum
def dehydrate(integer):
"""
Turn an integer [integer] into a base [BASE] number
in string representation
"""
# we won't step into the while if integer is 0
# so we just solve for that case here
if integer == 0:
return '0'
string = ""
while integer > 0:
remainder = integer % BASE
string = true_chr(remainder) + string
integer =int(integer/BASE)
return string
if __name__ == '__main__':
# not really unit tests just a rough check to see if anything is way off
if sys.argv[1] == '-tests':
passed_tests = True
for i in xrange(0, 1000):
passed_tests &= (i == saturate(dehydrate(i)))
print (passed_tests)
else:
user_input = sys.argv[2]
try:
if sys.argv[1] == '-s':
print (saturate(user_input))
elif sys.argv[1] == '-d':
print (dehydrate(int(user_input)))
else:
print ("I don't understand option %s" % sys.argv[1])
except ValueError as e:
print (e)
@Biglucky
Copy link
Author

@euclidr
Copy link

euclidr commented May 27, 2019

hey, I found a problem in this gist, in dehydrate function, if integer is very big the result will be wrong, because the division result is float type which can't represent every integer above 2^53.

In L80 we should use double slash // instead of /.

>>> mu64 = 18446744073709551615
>>> mu64 / 62 % 62
26.0
>>> (mu64 // 62) % 62
34

@AndreyeuIvan
Copy link

Row 88, xrange. One more change.

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment