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v2 with spin direction and increasing amount of segments per turn for smoother result in outer circles
import sys, os
import shutil
import math
import itertools
from copy import deepcopy
# 0 1 2 3 4 5 6
LIST_elmt = [" ("," (start ",") (end ",") "," (layer ",") ","))"]
#LIST_elmt = [" (gr_line (start 131.571908 182.314571) (end 112.874456 120.68499) (angle 90) (layer Dwgs.User) (width 0.1))"]
#LIST_elmt = [" (segment (start 118.7 106.7) (end 119.4 106.7) (width 0.25) (layer B.Cu) (net 0))"]
DICT_elmt = {"seg" : ["segment", "(width ", "(net "],
"arc" : ["gr_arc", "(angle ", "(width "],
"lne" : ["gr_line", "(angle ", "(width "],
}
DICT_lyr = { "dwg" : "Dwgs.User",
"cmt" : "Cmts.User",
"cut" : "Edge.Cuts",
"fcu" : "F.Cu",
"bcu" : "B.Cu",
}
def FNC_string (element,
STR_start, #1
STR_end, #2
Angle, #4
layer, #5
width,
):
STR_line = ""
"""
0 1 2 3 4 5
LIST_elmt = [" ("," (start ",") (end ",") "," (layer ",") (width ","))"]
"""
for i in range(len(LIST_elmt)):
STR_line += LIST_elmt[i]
if i == 0:
STR_line += DICT_elmt[element][0]
if i == 1:
STR_line += STR_start
if i == 2:
STR_line += STR_end
if i == 3:
if element == "seg":
STR_line += DICT_elmt[element][1]
STR_angle = "{:.1f}".format(width)
else:
STR_line += DICT_elmt[element][1]
if element == "lne":
STR_angle = "90"
else:
STR_angle = str(Angle)
STR_line += STR_angle + ")"
if i == 4:
STR_line += DICT_lyr[layer]
if i == 5:
if element == "seg":
STR_line += DICT_elmt[element][2]
STR_line += str(Angle)
else:
STR_line += DICT_elmt[element][2]
STR_line += "{:.2f}".format(width)
STR_line += "\n"
return STR_line
def FNC_polygon (element,
STR_start, #1
STR_end, #2
Angle, #4
layer, #5
width,
):
STR_line = ""
"""
0 1 2 3 4 5
LIST_elmt = [" ("," (start ",") (end ",") "," (layer ",") (width ","))"]
"""
for i in range(len(LIST_elmt)):
STR_line += LIST_elmt[i]
if i == 0:
STR_line += DICT_elmt[element][0]
if i == 1:
STR_line += STR_start
if i == 2:
STR_line += STR_end
if i == 3:
if element == "seg":
STR_line += DICT_elmt[element][1]
STR_angle = "{:.1f}".format(width)
else:
STR_line += DICT_elmt[element][1]
if element == "lne":
STR_angle = "90"
else:
STR_angle = str(Angle)
STR_line += STR_angle + ")"
if i == 4:
STR_line += DICT_lyr[layer]
if i == 5:
if element == "seg":
STR_line += DICT_elmt[element][2]
STR_line += str(Angle)
else:
STR_line += DICT_elmt[element][2]
STR_line += "{:.2f}".format(width)
STR_line += "\n"
return STR_line
def FNC_spiral (cntr, # (x,y)
radius,
segs,
startangle,
tw, # track width
td, # track distance
turns,
spin, # cw or ccw, +1 or -1
layer,
net,
):
STR_data = ""
baseX = cntr[0]
baseY = cntr[1]
for j in range(turns):
segs += 4.0
segangle = 360.0 / segs
segradius = td / segs
for i in range(int(segs)):
# central rings for HV and SNS
startX = baseX + (radius + segradius * i + td * (j+1)) * math.sin(math.radians(segangle*spin*i + startangle))
startY = baseY + (radius + segradius * i + td * (j+1)) * math.cos(math.radians(segangle*spin*i + startangle))
endX = baseX + (radius + segradius * (i + 1.0) + td * (j+1)) * math.sin(math.radians(segangle*spin*(i + 1.0) + startangle))
endY = baseY + (radius + segradius * (i + 1.0) + td * (j+1)) * math.cos(math.radians(segangle*spin*(i + 1.0) + startangle))
STR_data += FNC_string ("seg", #type of line
"{:.6f}".format(startX) + " " + "{:.6f}".format(startY), # start point
"{:.6f}".format(endX) + " " + "{:.6f}".format(endY), # end point
net, # angle or net value
layer, # layer on pcb
tw, # track width
)
return STR_data
if __name__ == '__main__':
Center = [115.0,105.0] # x/y coordinates of the centre of the pcb sheet
Radius = 0.5 # start radius in mm
Sides = 20.0
StartAngle = 0.0 # degrees
TrackWidth = 0.4
TrackDistance = 0.6
Turns = 8
Spin = -1 # ccw = +1, cw = -1
Layer = "fcu"
Net = "1"
print FNC_spiral (Center,
Radius,
Sides,
StartAngle,
TrackWidth,
TrackDistance,
Turns,
Spin,
Layer,
Net,
)
@edonnardkibii

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@edonnardkibii edonnardkibii commented Oct 16, 2019

Hallo, I'd like to know your license policy on this python code if you don't mind

@titojff

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@titojff titojff commented Oct 20, 2020

Excellent Job, a good addition would be
calculation of the coil inductance.

Nice job

@karelv

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@karelv karelv commented Dec 21, 2020

super! calculation of coil resistance would be nice as well!

@thomadan01

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@thomadan01 thomadan01 commented Mar 25, 2021

Thank you for this code!!

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