Skip to content

Instantly share code, notes, and snippets.

@ShirtlessKirk
Last active August 27, 2024 05:35
Show Gist options
  • Save ShirtlessKirk/2134376 to your computer and use it in GitHub Desktop.
Save ShirtlessKirk/2134376 to your computer and use it in GitHub Desktop.
Luhn validation algorithm
/**
* Luhn algorithm in JavaScript: validate credit card number supplied as string of numbers
* @author ShirtlessKirk. Copyright (c) 2012.
* @license WTFPL (http://www.wtfpl.net/txt/copying)
*/
var luhnChk = (function (arr) {
return function (ccNum) {
var
len = ccNum.length,
bit = 1,
sum = 0,
val;
while (len) {
val = parseInt(ccNum.charAt(--len), 10);
sum += (bit ^= 1) ? arr[val] : val;
}
return sum && sum % 10 === 0;
};
}([0, 2, 4, 6, 8, 1, 3, 5, 7, 9]));
@ShirtlessKirk
Copy link
Author

@afixibiranchi I see that your issue was answered on http://planetcalc.com/2464/ . I'm guessing you used the "number" on the example card image of https://www.mastercard.us/en-us/issuers/get-support/2-series-bin-expansion.html where it would make sense to be an invalid number...

@heymartinadams
Copy link

heymartinadams commented Sep 29, 2017

Wonderful! Thank you.

@yevhen-chornohradskyi
Copy link

yevhen-chornohradskyi commented Oct 26, 2017

@ShirtlessKirk OMFG
Phil, dude, who could've imagined it'would be your implementation of Luhn check I'm gonna use?!

@jonbodner
Copy link

@ShirtlessKirk I'd like to use this luhn implementation, but my employer forbids software licensed under WTFPL. Can you relicense or dual-license under BSD or MIT?

@JurgenBlitz
Copy link

Wonderful implementation. I worked a very basic solution to adapt this algorithm to TypeScript, feel free to use or comment on improvements:
`
public luhnAlgorithmCheck(ccNum) {
const arr = [0, 2, 4, 6, 8, 1, 3, 5, 7, 9];
let len = ccNum.length;
let bit = 1;
let sum = 0;
let val;

while (len) {
  val = parseInt(ccNum.charAt(--len), 10);
  // tslint:disable-next-line:no-bitwise
  sum += (bit ^= 1) ? arr[val] : val;
}
return sum && sum % 10 === 0;

}
`
Thanks for sharing the original code, @ShirtlessKirk

@jensb1
Copy link

jensb1 commented Mar 12, 2020

"12345678".split("").reverse().map(function(c, i) { return ((i%2==0 ? 1 : 2)*parseInt(c)) }).join("").split("").map((c) => parseInt(c)).reduce(function(sum, c) { return sum+=parseInt(c) })

@emandeguzman
Copy link

emandeguzman commented Apr 23, 2020

I tested against https://www.paypalobjects.com/en_US/vhelp/paypalmanager_help/credit_card_numbers.htm

76009244561 did not return true

But I'm not sure if this number is really valid. all luhn verification code seem to fail when I use this number.

@jefelewis
Copy link

@ShirtlessKirk What does the array at the end do?

}([0, 2, 4, 6, 8, 1, 3, 5, 7, 9]));

@ShirtlessKirk
Copy link
Author

@jefelewis it's a lookup table. Basically, instead of calculating the summed result of the numbers that are doubled (every second digit from right) each time, the code uses the precalculated value stored in the array at the index of the digit in question.

For example, if the digit is 6, the summed double is 3 (6 * 2 = 12, 1 + 2 = 3). In the array, the value at index 6 (the original digit used as a reference) is set to 3.

@bdr193
Copy link

bdr193 commented May 10, 2022

@ShirtlessKirk Can this be implemented in Shopify or Woocommerce? How can you install it without having access to the payment iframe

@carlosvega20
Copy link

Declarative/functional approach:

const checkLuhn = cardNumber => {
    const sum = [...cardNumber].reduceRight((prev, curr, i, arr) =>
        prev+= (i%2)?Number(arr[Number(curr)]):Number(curr)
    ,0);
    return sum && sum % 10 === 0;
}

https://gist.github.com/carlosvega20/8ec8b472de22626a70a65f5893de82e9?permalink_comment_id=4748205#gistcomment-4748205

@Yana-Lesina
Copy link

Yana-Lesina commented May 17, 2024

@carlosvega20 I'm a bit confused by Number(arr[Number(curr)]) expression and not sure if this works correctly for check

Can suggest instead smth like this:

const isLuhn = (cardNumber) => {
  const checkSum = [...cardNumber].reduceRight((prev, curr, i, arr) => {
    if(i % 2) {
      return prev += Number(curr);
    } else {
      const d  = Number(curr) * 2 
      return prev += d > 9 ? d - 9 : d
    }
  }, 0);
    
  return checkSum && checkSum % 10 === 0
}

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment