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@aitatanit
Forked from blink1073/dict_to_table.py
Last active August 29, 2015 14:10
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"""
Given an arbitrarily nested dictionary, create a PyTables Table
Populate a table row given the contents of a dictionary
"""
import tables
import numpy as np
import sys
if sys.version.startswith('3'):
unicode = str
def get_dtype(data):
"""Given a dict, generate a nested numpy dtype"""
fields = []
for (key, value) in data.items():
# make strings go to the next 64 character boundary
# pytables requires an 8 character boundary
if isinstance(value, unicode):
value += u' ' * (64 - (len(value) % 64))
# pytables does not support unicode
if isinstance(value, unicode):
value = value.encode('utf-8')
elif isinstance(value, str):
value += ' ' * (64 - (len(value) % 64))
if isinstance(value, dict):
fields.append((key, get_dtype(value)))
else:
value = np.array(value)
fields.append((key, '%s%s' % (value.shape, value.dtype)))
return np.dtype(fields)
def _recurse_row(row, base, data):
for (key, value) in data.items():
new = base + key
if isinstance(value, dict):
_recurse_row(row, new + '/', value)
else:
row[new] = value
def add_row(tbl, data):
"""Add a new row to a table based on the contents of a dict.
"""
row = tbl.row
for (key, value) in data.items():
if isinstance(value, dict):
_recurse_row(row, key + '/', value)
else:
row[key] = value
row.append()
tbl.flush()
if __name__ == '__main__':
data = dict(a=1, e=dict(c='1', b=[1, 2, 3],
f=dict(foo='bar')))
dtype = get_dtype(data)
print(dtype)
fid = tables.open_file('test.h5', 'w')
grp = fid.create_group('/', 'foo')
tbl = fid.create_table(grp, 'bar', dtype)
add_row(tbl, data)
assert tbl.read(0)['e']['c'].astype(np.str) == '1'
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