Lab 7b.py

print("This Program converts  to Pig Latin, then prints both the original word and the Pig Latin version to the console. The program continues reading words until the user enters 'stop'.")


def pigLatin(ll):
    flag = 0
    if(ll[0] == "a" or ll[0] == "e" or ll[0] == "i" or ll[0] == "o" or ll[0]== "u" or ll[0] == "y"):
        flag = 1
    elif(ll[0] == "A" or ll[0] == "E" or ll[0] == "I" or ll[0] == "O" or ll[0]== "U" or ll[0] == "Y"):
        flag = 1
    if(flag == 1):
        s = ll[1:] + ll[0]
        s = s + "ay"
    # All you need to do here is to write an else block with what happens if the flag is not set.
    # The issue is that if the start of the word does not start with a vowel, s is not defined.
    # Example s("hi") -> Error
    # Example s("i") -> iay
    # So add something like:
    # else: s = ll + 'yay'
    return(s)
    
s = ""
while(s!= "stop"):
    s = input("Enter a word to convert to pig Latin enter stop to end: ")
    if(s != "stop"):
        p = pigLatin(s)
        print(s +" is pig latin is: " + p)

As I was saying, a cleaner option might be to do something like this:

startsWithVowel = word[0].lower() in {'a', 'e', 'i', 'o', 'u', 'y'}
if(startsWithVowel): s = word[1:] + word[0] +  'ay'
else: s = word + 'yay'

Make sure you handle the case in which ll = the_word = ''

word = " "
while(s!= "stop"):
s = input("Enter a word to convert to pig Latin enter stop to end: ")
if(s != "stop"):
startsWithVowel = word[0].lower() in {'a', 'e', 'i', 'o', 'u', 'y'}
if(startsWithVowel):
s = word[1:] + word[0] + 'ay'
else:
s = word + 'yay'
print(s, " is pig latin is: " )

word = ""
while(word != "stop"):
    word = input("Enter a word to convert to pig Latin enter stop to end: ")
    if(word != "stop"):
        startsWithVowel = word[0].lower() in {'a', 'e', 'i', 'o', 'u', 'y'}
        if(startsWithVowel): pigWord = word + 'yay'
        else: pigWord = word[1:] + word[0] + 'ay'
    print(word, " is pig latin is: ", pigWord)