Sort docker images by size desc

docker-image-size.sh

#!/bin/sh
docker images --format '{{.Size}}\t{{.Repository}}\t{{.Tag}}\t{{.ID}}' | sed 's/ //' | sort -h -r | column -t

@cuongtransc thanks. have updated with the column -t

docker images | sort -k7 -h

Showing & keeping the leading column title where they are:

docker images | awk 'NR<2{print $0;next}{print $0| "sort -k7 -hr"}'

Add | head to get only the biggest ones

docker images | sort -k7 -h

@quantonganh Like a pro! :) Kudos.

To be clear, its -k7, not -k5, because there are generally two spaces in the preceding CREATED column

Nice, very clear, could used by default...unuseful to me though because it's not a real sort by size that I looked for, I'll keep searching, thx anyway...

docker images | sort -k7 -h

@quantonganh Great one! I just added an -r to show the biggest image first:

docker images | sort -k7 -h -r

docker images | sort -k7 -h

@quantonganh I referenced your command in another post.

I had to replace the decimal separator in dockers {{.Size}} which seems to be always a dot, with the one of my locale to make sort -h work properly.

docker images --format '{{.Size}}\t{{.Repository}}:{{.Tag}}\t{{.ID}}' | sed 's/\./,/' | sort -hr | column -t

Note: the sed command blindly replaces the first "." per line.

I had to replace the decimal separator in dockers {{.Size}} which seems to be always a dot, with the one of my locale to make sort -h work properly.

Setting locale collate would do the trick as well. Something like this should work too:
docker images | LC_COLLATE=C.UTF-8 sort -k7 -hr