gistfile1.js

  var Q = require('q');

  var allPromises = function (arrayOfThings) {
    var promises = [];
    arrayOfThings.forEach(function(aThing) {
      console.log('updating a thing: ' + aThing);
      var promise = Q.fcall(function () {
          console.log("in func promise");
          return 'something';
        })
        .delay(1000)
        .done(function() {
          console.log('done with func promise');
        });
      promises.push(promise);
    });
    console.log('returning a promise');
    return Q.allResolved(promises);
  };

  allPromises(['a', 'b', 'c'])
    .done(function() {
      console.log('done with everything');
    }
  );

I would expect 'done with everything' to show up last. But no matter how rework allPromises, I always see it have the potential of going last. (The delay is in allPromises to make sure that it can be seen that allPromises happens last.) Here's the output from the above:

updating a thing: a
updating a thing: b
updating a thing: c
returning a promise
in func promise
in func promise
in func promise
done with everything
done with func promise
done with func promise
done with func promise

Switching "done" to "then" in the function is the answer, so that the "promise" variable actually has a promise.