gistfile1.js

  var Q = require('q');

  var allPromises = function (arrayOfThings) {
    var promises = [];
    arrayOfThings.forEach(function(aThing) {
      console.log('updating a thing: ' + aThing);
      var promise = Q.fcall(function () {
          console.log("in func promise");
          return 'something';
        })
        .delay(1000)
        .done(function() {
          console.log('done with func promise');
        });
      promises.push(promise);
    });
    console.log('returning a promise');
    return Q.allResolved(promises);
  };

  allPromises(['a', 'b', 'c'])
    .done(function() {
      console.log('done with everything');
    }
  );

Switching "done" to "then" in the function is the answer, so that the "promise" variable actually has a promise.