bhagatparwinder

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bhagatparwinder

What

LinkedIn is a valuable resource, but sometimes it sucks. One of those times is when you want to delete messages. You have to select each message one by one. It takes about 4 "clicks" to successfully delete a message.

This script should help. Since LI requires you to perform multiple steps, I decided to automate it for you. Once you initiate the script, it will run every second. If a message has the ability to be deleted, it will be. If not, it will be archived. Some "InMail" messages cannot be deleted on the web app. This script should work as long as LI doesn't change their page layout or element names, which happens often.

Last tested & verified working on: June, 10, 2022

Special Thanks to @noncent for the updated script.

bhagatparwinder

# use ImageMagick convert
# the order is important. the density argument applies to input.pdf and resize and rotate to output.pdf
convert -density 90 input.pdf -rotate 0.5 -attenuate 0.2 +noise Multiplicative -colorspace Gray output.pdf

bhagatparwinder

// Takes a credit card string value and returns true on valid number
function valid_credit_card(value) {
  // Accept only digits, dashes or spaces
	if (/[^0-9-\s]+/.test(value)) return false;

	// The Luhn Algorithm. It's so pretty.
	let nCheck = 0, bEven = false;
	value = value.replace(/\D/g, "");

	for (var n = value.length - 1; n >= 0; n--) {

bhagatparwinder

#!/bin/sh

set -e
set -x

for package in $(npm -g outdated --parseable --depth=0 | cut -d: -f3)
do
    npm -g install "$package"
done

bhagatparwinder

// create a bookmark and use this code as the URL, you can now toggle the css on/off
// thanks+credit: https://dev.to/gajus/my-favorite-css-hack-32g3
javascript: (function() {
	var elements = document.body.getElementsByTagName('*');
	var items = [];
	for (var i = 0; i < elements.length; i++) {
		if (elements[i].innerHTML.indexOf('* { background:#000!important;color:#0f0!important;outline:solid #f00 1px!important; background-color: rgba(255,0,0,.2) !important; }') != -1) {
			items.push(elements[i]);
		}
	}