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@bortels
Created December 6, 2011 05:56
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Base64 encode/decode for Codea (Lua)
-- Lua 5.1+ base64 v3.0 (c) 2009 by Alex Kloss <alexthkloss@web.de>
-- licensed under the terms of the LGPL2
-- character table string
local b='ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/'
-- encoding
function enc(data)
return ((data:gsub('.', function(x)
local r,b='',x:byte()
for i=8,1,-1 do r=r..(b%2^i-b%2^(i-1)>0 and '1' or '0') end
return r;
end)..'0000'):gsub('%d%d%d?%d?%d?%d?', function(x)
if (#x < 6) then return '' end
local c=0
for i=1,6 do c=c+(x:sub(i,i)=='1' and 2^(6-i) or 0) end
return b:sub(c+1,c+1)
end)..({ '', '==', '=' })[#data%3+1])
end
-- decoding
function dec(data)
data = string.gsub(data, '[^'..b..'=]', '')
return (data:gsub('.', function(x)
if (x == '=') then return '' end
local r,f='',(b:find(x)-1)
for i=6,1,-1 do r=r..(f%2^i-f%2^(i-1)>0 and '1' or '0') end
return r;
end):gsub('%d%d%d?%d?%d?%d?%d?%d?', function(x)
if (#x ~= 8) then return '' end
local c=0
for i=1,8 do c=c+(x:sub(i,i)=='1' and 2^(7-i) or 0) end
return string.char(c)
end))
@yunyyyun
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yunyyyun commented Aug 1, 2017

in line 32 it mast be "for i=1,8 do c=c+(x:sub(i,i)=='1' and 2^(8-i) or 0) end" ?

@Karakurt1988
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Hey. how to add support for another language?

@tormyvancool
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in line 32 it mast be "for i=1,8 do c=c+(x:sub(i,i)=='1' and 2^(8-i) or 0) end" ?

Yes it's 8. He didn't correct it yet

@bortels
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Author

bortels commented Jun 1, 2021

"yet"? It's a decade old and not my code - I just copied/pasted it here for a project long ago. 7 years ago rafis posted a link to a proper version. Go use that. FWIW - It worked when I used it way back when. YMMV.

@sk556
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sk556 commented Jun 2, 2021

Giỏi.yith"÷%(×'

@sk556
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sk556 commented Jun 2, 2021

Higiy

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