num_a_or_e.py

# Write code that counts the number of words in sentence that contain either an “a” or an “e”.
# Store the result in the variable num_a_or_e.
# Note 1: be sure to not double-count words that contain both an a and an e.
# HINT 1: Use the in operator.
# HINT 2: You can either use or or elif.
# Hard-coded answers will receive no credit.

sentence = "python is a high level general purpose programming language that can be applied to many different classes of problems."

num_a_or_e = 0
for i in sentence.split():
    if ('a' in i) or ('e' in i):
        num_a_or_e += 1

print(num_a_or_e)

sentence = "python is a high level general purpose programming language that can be applied to many different classes of problems."
items = sentence.split(" ")
num_a_or_e=0
print (items)

for y in items:
if (y.count("a"))>0:
num_a_or_e+=1
#print (y)
print (num_a_or_e)
elif (y.count("e"))>0:
num_a_or_e+=1
#print (y)
print (num_a_or_e)