Last active
September 27, 2022 20:51
-
-
Save codecakes/e4cb337107615a5074f20942ad52ce01 to your computer and use it in GitHub Desktop.
minimum window substring
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
""" | |
Given two strings s and t of lengths m and n respectively, | |
return the minimum window substring of s such that every character in t (including duplicates) | |
is included in the window. | |
If there is no such substring, return the empty string "". | |
A substring is a contiguous sequence of characters within the string. | |
This is fucking hard. | |
""" | |
from collections import Counter | |
# This solution will work for base test cases but not for exhaustive cases: | |
class Solution: | |
def minWindow(self, s: str, t: str) -> str: | |
if t == "": return "" | |
left = 0 | |
test_str_ctr = {} | |
p_ctr = {} | |
p_ctr.update(Counter(t)) | |
ctr_items = sum(p_ctr.values()) | |
min_len = float("inf") | |
min_str = (0, 0) | |
total_ct = 0 | |
print("before, total_ct, left, right, char, test_str_ctr, p_ctr") | |
for right, char in enumerate(s): | |
if char in p_ctr: | |
test_str_ctr[char] = test_str_ctr.get(char, 0) + 1 | |
if test_str_ctr[char] == p_ctr[char]: | |
total_ct += 1 # this is not needed! understand the concept. this is a hack. | |
# print("before", total_ct, left, right, char, test_str_ctr, p_ctr) | |
while total_ct == ctr_items: | |
if min_len > right - left + 1: | |
min_str = (left, right+1) | |
min_len = right - left + 1 | |
char = s[left] | |
if char in p_ctr: | |
test_str_ctr[char] -= 1 | |
if test_str_ctr[char] < p_ctr[char]: | |
total_ct -= 1 | |
left += 1 | |
# print("after", total_ct, left, right, char, test_str_ctr, p_ctr) | |
res = "" | |
for c_idx in range(*min_str): | |
res += s[c_idx] | |
return res | |
# This resolves the issue. Conceptually, | |
# you need to compare that all frequencies of each character are >= in target string | |
from collections import Counter | |
from functools import partial | |
class Solution: | |
@staticmethod | |
def minimumDictValCount(src_dict: dict, target_dict: dict): | |
return all(src_dict.get(k, 0) >= v for k,v in target_dict.items()) | |
def minWindow(self, s: str, t: str) -> str: | |
if t == "": return "" | |
left = 0 | |
target_len = len(t) | |
test_str_ctr = {} | |
p_ctr = {} | |
p_ctr.update(Counter(t)) | |
min_len = float("inf") | |
min_str = (0, 0) | |
total_ct = 0 | |
hasMinSumOfWindow = partial(self.minimumDictValCount, test_str_ctr, p_ctr) | |
for right, char in enumerate(s): | |
if char in p_ctr: | |
test_str_ctr[char] = test_str_ctr.get(char, 0) + 1 | |
while ( | |
test_str_ctr == p_ctr or hasMinSumOfWindow()): | |
if min_len > right - left + 1: | |
min_str = (left, right+1) | |
min_len = right - left + 1 | |
char = s[left] | |
if char in p_ctr: | |
test_str_ctr[char] -= 1 | |
left += 1 | |
res = "" | |
for c_idx in range(*min_str): | |
res += s[c_idx] | |
return res | |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment