Trying to get war file name from SBT

gistfile1.scala

object MyBuild extends Build {

  import BuildSettings._

  val custom = TaskKey[Unit]("custom", "Does custom processing")

  val customTask = custom := {
    Process("./a-script.sh %s".format(warFilePath), "a directory") !
  }
}

Here's what i could come up with in 5 quick minutes. If you run this with sbt, you should have a "my-task" available in the sbt shell that runs "ls -la " with the war file:
edit: github swallowed the $lessthan characters
edit2: gave up, please look at my fork: https://gist.github.com/1105498

Thanks for your help, Gerolf!

Not a problem at all. Glad to help out a fellow scalarazzi ;)

On Wed, Jul 27, 2011 at 12:02 AM, dcbriccetti < ***@***.***>wrote: Thanks for your help, Gerolf! ## Reply to this email directly or view it on GitHub: https://gist.github.com/1105497

## Gerolf Seitz twitter: @gersei code: github.com/gseitz blog: www.gerolfseitz.com