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Created June 27, 2013 18:15
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Flatten an Array Recursively
# Flatten an Array Recursively
# Imagine we have an array that potentially contains other arrays, e.g.,
# ["bananas", [1,2,3], ["apple", "cheese", [100, 20]], [true], [4.0, 7, 32]]
# Write a recursive method flatten that takes as its input an array and returns a fully flattened array.
#
# For example, using the above array flatten should work thus:
# array = ["bananas", [1,2,3], ["apple", "cheese", [100, 20]], [true], [4.0, 7, 32]]
# flatten(array) # => ["bananas", 1, 2, 3, "apple", "cheese", 100, 20, true, 4.0, 7, 32]
# You can see that it "flattens" an array of arrays into an array that contains no arrays.
# If the input array contains no arrays it should just return the input array, e.g.,
# flatten([1,2,3]) # => [1,2,3]
# Remember, you should do this recursively.
# Also remember, recursive doesn't mean "no loops." It means a method that calls itself.
def flatten(array, flattened_array=[])
array.each do |element|
if element.class == Array
flatten(element, flattened_array)
else
flattened_array << element
end
end
flattened_array
end
# Test code:
array = ["bananas", [1,2,3], ["apple", "cheese", [100, 20]], [true], [4.0, 7, 32]]
p flatten(array) #["bananas", 1, 2, 3, "apple", "cheese", 100, 20, true, 4.0, 7, 32]
# Next up, for those who got it to work, can you write it with two constraints:
# 1. No iteration inside the method (inject, each, map, etc. not allowed)
# 2. No other arguments besides the input array
def flatten(array)
return [] if array.empty?
flat = array.shift
flat = flat.class == Array ? flatten(flat) : [flat]
flat + flatten(array)
end
# Test code:
array = ["bananas", [1,2,3], ["apple", "cheese", [100, 20]], [true], [4.0, 7, 32]]
p flatten(array) #["bananas", 1, 2, 3, "apple", "cheese", 100, 20, true, 4.0, 7, 32]
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