Get Youtube video urls

gistfile1.txt

// Run from the dev tools console of any Youtube video
// Accurate as of July 2, 2020.
//
// Copy and paste this into the dev console in a browser with the desired video loaded.
//
// NOTE: Some Youtube videos do not directly expose the video url in the response. 
// This script doesn't currently attempt to handle those. It will work for most other general video types though.

(async () => {
  const html = await fetch(window.location.href).then((resp) => resp.text()).then((text) => text);
  const startStr = 'ytplayer.config = {';
  const start = html.indexOf(startStr) + startStr.length - 1;
  const end = html.indexOf('};', start) + 1;
  const playerObj = JSON.parse(html.slice(start, end));

  playerObj.args.player_response = JSON.parse(playerObj.args.player_response);

  const videoUrls = playerObj.args.player_response.streamingData.adaptiveFormats.reduce((acc, item) => {
    if (!acc[item.quality]) {
      acc[item.quality] = {};
    }

    const mimeType = item.mimeType.split(';')[0];

    acc[item.quality][mimeType] = item;

    return acc;
  }, {});

  console.log('!!', videoUrls);
})();

Uncaught (in promise) TypeError: Cannot read property 'split' of undefined
It shows this error everytime I run it.
I get the url of the page when by using window.location.href but I need the url which contains other properties such as screen-resolution, frame-rate, bit-rate , etc.

I also tried using ifram api by using src="https://www.youtube.com/get_video_info?video_id={videoId}" but the file which it returns gives this error status=fail&errorcode=2&reason=Invalid+parameters..

Please help if you can.

@Joshuajrodrigues @jarvis1234d script is now updated. Try it out.

It works with the updated july 2nd script, thank you @geuis

however the url from every object only contains video stream. Is there a way to get the url for a full video+audio stream?

After running the script what's the field that hold the url? I suppose that is the one named signatureCypher ? It starts with "s=yy.." so how to extract the url?

For Download video with audio

(async () => {
  html = await fetch(window.location.href).then(resp => resp.text()).then(text => text);
  startStr = 'ytplayer.config = {';
  start = html.indexOf(startStr) + startStr.length - 1;
  end = html.indexOf('};', start) + 1;
  playerObj = JSON.parse(html.slice(start, end));
  playerObj.args.player_response = JSON.parse(playerObj.args.player_response);
  videoUrls = playerObj.args.player_response.streamingData.formats[1].url;
  videoUrls = videoUrls.replace('"', 'r');
  return console.log(videoUrls);
})();

For Download video with audio

(async () => {
  html = await fetch(window.location.href).then(resp => resp.text()).then(text => text);
  startStr = 'ytplayer.config = {';
  start = html.indexOf(startStr) + startStr.length - 1;
  end = html.indexOf('};', start) + 1;
  playerObj = JSON.parse(html.slice(start, end));
  playerObj.args.player_response = JSON.parse(playerObj.args.player_response);
  videoUrls = playerObj.args.player_response.streamingData.formats[1].url;
  videoUrls = videoUrls.replace('"', 'r');
  return console.log(videoUrls);
})();

Thank you, this works great!

For Download video with audio

(async () => {
  html = await fetch(window.location.href).then(resp => resp.text()).then(text => text);
  startStr = 'ytplayer.config = {';
  start = html.indexOf(startStr) + startStr.length - 1;
  end = html.indexOf('};', start) + 1;
  playerObj = JSON.parse(html.slice(start, end));
  playerObj.args.player_response = JSON.parse(playerObj.args.player_response);
  videoUrls = playerObj.args.player_response.streamingData.formats[1].url;
  videoUrls = videoUrls.replace('"', 'r');
  return console.log(videoUrls);
})();

Thank you, this works great!

I've tried the script but I get a reject in promise. Seems not working. TypeError: Cannot read property 'url' of undefined↵ at <anonymous>:8:71

in what language is it written in? I need to rewrite it to swift

@nysander - did you ever get this converted to Swift?

in what language is it written in? I need to rewrite it to swift

@nysander - did you ever get this converted to Swift?

Nope because Apple is very strict with playback rights and I have dropped idea of this script in my app