Convert a filename into a Python module name

python-module-name

#!/usr/bin/env zsh

setopt \
	err_exit \
	pipe_fail \
	warn_create_global \
	warn_nested_var \
	no_unset

version='1.0.0'

help='Usage:
  python-module-name [options] <file> [files...] 

Options:
  -V/--version          Show the program version and exit.
  -h/--help             Show this text and exit.
  -t/--toplevel <path>  Set the "top level" directory for module names. Defaults to
                        `-t .` if omitted. Similar to Python `unittest -t`.'

typeset -A opts=(
	'--toplevel' '.'
)
zparseopts -D -K -M -A opts \
	-help h=-help \
	-version V=-version \
	-toplevel: t:=-toplevel

if (( ${+opts[--help]} != 0 )); then
	print -- "$help"
	exit 0
fi

if (( ${+opts[--version]} != 0 )); then
	print -- "$version"
	exit 0
fi

toplevel=${opts[--toplevel]:a}

if (( $# < 1 )); then
	print -u2 -- 'Not enough arguments: at least one filename is required.'
	print -u2 -- ''
	print -u2 -- "$help"
	exit 2
fi

for file in "$@"; do
	module_source=${file:a}
	if [[ ${module_source:t} = '__init__.py' ]]; then
		module_source=${module_source:h}
	fi
	module_name=${${${${module_source%.py}#$toplevel}#/}//\//.}
	print -- $module_name
done