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Midnight CTF 2018 Finals - Snurre128
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#-*- coding:utf-8 -*- | |
''' | |
Writeup: | |
http://mslc.ctf.su/wp/midnight-ctf-2018-finals-snurre128/ | |
... | |
Solution found: | |
130306609594991829769917756515894243368 | |
midnight{620823e005ad9340e1dd7da6deb13028} | |
real 35m58.502s | |
user 35m44.309s | |
sys 0m12.855s | |
''' | |
from sage.all import * | |
KS = eval(open("keystream.txt").read()) | |
assert len(KS) == 1600 | |
from snurre128 import Snurre128 | |
m = matrix(GF(2), 1600, 128) | |
for i in xrange(128): | |
print "Column", i | |
s = Snurre128(1 << (127 - i)) | |
m.set_column(i, list(s.keystream(1600, linear=True))) | |
print "Matrix generated" | |
k = 128 | |
n = 1600 | |
r = 1/QQ(16) + 1/QQ(32) | |
mcheck = m[:256] | |
vcheck = vector(GF(2), KS[:256]) | |
itr = 0 | |
while True: | |
itr += 1 | |
# choose random invertible k*k submatrix | |
sub = matrix(GF(2), 0, k) | |
inds = [] | |
while True: | |
i = randint(0, n-1) | |
subx = sub.stack(m.row(i)) | |
if subx.rank() > sub.rank(): | |
inds.append(i) | |
sub = subx | |
if sub.rank() == k: | |
break | |
out = vector(GF(2), [KS[i] for i in inds]) | |
try: | |
sol = sub.solve_right(out) | |
except ValueError: | |
continue | |
test = mcheck * sol + vcheck | |
test = sum(map(int, test)) | |
print "sol", itr, "hw", test, "/", len(vcheck) | |
if test > 64: | |
continue | |
v = 0 | |
for b in sol: | |
v = (v << 1) | int(b) | |
print "Solution found:" | |
print v | |
print "midnight{%x}" % v | |
break |
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import os | |
class Snurre128: | |
""" | |
Snurre128 is a proprietary stream cipher designed for | |
high-sensitive applications such as top-secret classified | |
government data. It is recommended by top cryptographers | |
along the world. | |
It has the following structure: | |
+--------+----+------+ | |
| | | | | |
+---+---+- -+---+ | | |
| | | ... | | <--+ | |
+---+---+- -+---+ | |
| | | |
+---------------+ | |
| f | --> c | |
+---------------+ | |
Snurre128 is resistant to *all* attacks, since it uses | |
a perfect boolean function f as output function. | |
Snurre128 is quantum secure and blockchain ready. It | |
is the stream cipher of the future. It is 100 % cyber. | |
We charge a reasonable fee of $0.00001 / encrypted bit. | |
-- The Designers | |
""" | |
def __init__(self, key): | |
self.state = key | |
self.mask = 528457622443627673964173138273112871261 | |
self.nbits = self.mask.bit_length()-1 | |
def output(self, linear=False): | |
var = bin(self.state)[2:].zfill(self.nbits) | |
v = [int(v) for v in var] | |
if linear: | |
return v[0] ^ v[1] ^ v[2] ^ v[31] | |
return v[0] ^ v[1] ^ v[2] ^ v[31] ^ \ | |
v[1]&v[2]&v[3]&v[64]&v[123] ^ \ | |
v[25]&v[31]&v[32]&v[126] | |
def __str__(self): | |
j = 0 | |
poly = [] | |
x = self.mask | |
while x > 0: | |
if x & 1: | |
poly = ["x^{}".format(j)] + poly | |
x >>= 1 | |
j += 1 | |
return " + ".join(poly) | |
def keystream(self, n, linear=False): | |
for _ in xrange(n): | |
self.state = (self.state << 1) | |
xor = self.state >> self.nbits | |
if xor != 0: | |
self.state ^= self.mask | |
yield self.output(linear=linear) | |
if __name__ == '__main__': | |
from random import randint | |
k = 106591834343745538540229882011251519916 | |
print "k =", k | |
s = Snurre128(k) | |
print list(s.keystream(1600)) |
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