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# johndyer/easter.js

Last active Apr 21, 2022
Calculate Easter in JavaScript
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 /** * Calculates Easter in the Gregorian/Western (Catholic and Protestant) calendar * based on the algorithm by Oudin (1940) from http://www.tondering.dk/claus/cal/easter.php * @returns {array} [int month, int day] */ function getEaster(year) { var f = Math.floor, // Golden Number - 1 G = year % 19, C = f(year / 100), // related to Epact H = (C - f(C / 4) - f((8 * C + 13)/25) + 19 * G + 15) % 30, // number of days from 21 March to the Paschal full moon I = H - f(H/28) * (1 - f(29/(H + 1)) * f((21-G)/11)), // weekday for the Paschal full moon J = (year + f(year / 4) + I + 2 - C + f(C / 4)) % 7, // number of days from 21 March to the Sunday on or before the Paschal full moon L = I - J, month = 3 + f((L + 40)/44), day = L + 28 - 31 * f(month / 4); return [month,day]; }

### DHFW commented May 29, 2019

Thank you!

For others: be aware that this returns the month as 1 = January, 2 = February and so on.

I subtracted the month with one to be able to convert it to a Javascript Date easily in which the month is index based (0 = January, 1 = February).

### varvino commented Feb 6, 2020

Thanks a lot for this

### gavinr commented Mar 10, 2020

I am using this here: Easter Dates
Thanks!

### sunsero commented Apr 11, 2020

Is it just me or is the function returning Easter Monday this year? Happy Easter, anyway!

### sunsero commented Apr 11, 2020

Don't think so because Easter Sunday is calculated for 2019 and for 2021 correctly. If it matters I'm during summer time in UTC+2, in winter in UTC+1.

### johndyer commented Apr 11, 2020

`getEaster(2020); `
returns
`[4, 12]`
for me...

### sunsero commented Apr 11, 2020

Thanks, you're right - if I pass 2020 as a constant value rather than in a variable it gives the correct result. I'll have to figure out what's going on.

### Termplexed commented Mar 1, 2021

Minor nuisance. On line 12 there is thin-space in stead of normal space. (`0x2009` instead of `0x20`) in `C - f`

`		H = (C<0x2009>-<0x2009>f(C / 4) - f((8 * C + 13)/25) + 19 * G + 15) % 30,`

### johndyer commented Mar 1, 2021

Thanks @Termplexed! Fixed.

### creat73 commented Apr 1, 2021

This algorithm seems to fail for year 2022 returning 23.04 instead of 17.04. Works fine for any other year I tried. Any idea on why that might be? I'm really curious and couldn't find explanation.

### wysal commented Jun 9, 2021 • edited

I needed to count days up from easter for public holidays calculation so I did some adaptions:

function getEaster(year, plusdays) {
var f = Math.floor,
G = year % 19,
C = f(year / 100),
H = (C - f(C / 4) - f((8 * C + 13) / 25) + 19 * G + 15) % 30,
I = H - f(H / 28) * (1 - f(29 / (H + 1)) * f((21 - G) / 11)),
J = (year + f(year / 4) + I + 2 - C + f(C / 4)) % 7,
L = I - J,
month = 3 + f((L + 40) / 44),
day = L + 28 - 31 * f(month / 4);
return new Date(year, month - 1, day + plusdays);
}

so this would then output for example Easter Monday:
`getEaster(2022, 1)`

in case of need for someone

### tdiluzio commented Nov 22, 2021

Thanks @johndyer and @wysal 👍

### P06316 commented Nov 26, 2021 • edited

This algorithm seems to fail for year 2022 returning 23.04 instead of 17.04. Works fine for any other year I tried. Any idea on why that might be? I'm really curious and couldn't find explanation.

I had the same issue and solved it by applying parseInt(myYear, 0) on the variable containing the year.

console.log(getEaster("2022")); //Returns [4, 23] => NOK
console.log(getEaster(2022)); //Returns [4, 17] => OK
console.log(getEaster(parseInt("2022", 0))); //Returns [4, 17] => OK

### PenkoMlakar commented Mar 18, 2022

Thanks @johndyer!