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@kennethreitz
Created May 16, 2011 00:17
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urllib2 vs requests
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import urllib2
gh_url = 'https://api.github.com'
req = urllib2.Request(gh_url)
password_manager = urllib2.HTTPPasswordMgrWithDefaultRealm()
password_manager.add_password(None, gh_url, 'user', 'pass')
auth_manager = urllib2.HTTPBasicAuthHandler(password_manager)
opener = urllib2.build_opener(auth_manager)
urllib2.install_opener(opener)
handler = urllib2.urlopen(req)
print handler.getcode()
print handler.headers.getheader('content-type')
# ------
# 200
# 'application/json'
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import requests
r = requests.get('https://api.github.com', auth=('user', 'pass'))
print r.status_code
print r.headers['content-type']
# ------
# 200
# 'application/json'
@debambi
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debambi commented Jan 3, 2020

@trami996
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trami996 commented Jun 8, 2021

Và có vẻ như bạn có thể đơn giản hóa nó hơn nữa:

nhập  urllib2 
từ  base64  nhập  b64encode

yêu cầu  =  urllib2 . Yêu cầu ( 'https://api.github.com/user' )  <meta property="fb:pages" content="112008217311363" /> _header ( 'Ủy quyền' , 'Cơ bản'  +  b64encode ( 'user'  +  ':'  +  'pass' ))
 r  =  urllib2 . urlopen ( yêu cầu )

in  r . getcode ()
 print  r . headers [ "content-type" ]
 print  r . tiêu đề [ "X-RateLimit-Limit" ]

Vì vậy, nó chỉ có 3 dòng và nó tương thích với urllib2cuộc gọi thông thường . Vì vậy, mặc dù API của urllib2thực sự không tốt, nhưng nó không tệ như ví dụ ban đầu của bạn. Vì vậy, tôi nghĩ rằng bạn nên sử dụng phiên bản 3 dòng này để thay thế cho công bằng.

CHỈNH SỬA: Đảm bảo rằng bạn sử dụng b64encodechức năng trên. Sau đó, bạn không cần xóa dấu '\ n' theo sau khỏi chuỗi.

CHỈNH SỬA 2: Đơn giản hơn một chút. Tôi nghĩ nó đơn giản như bây giờ.

@mangalan516
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It's look interesting guys keep going.

@chajun2106
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chajun2106 commented Jun 23, 2021

Já utilizaram request no Plone versão 4.3.18? Com os mesmo códigos sugeridos, tenho no Plone resposta de "Privilegios Insuficientes."

Have you already used request in Plone version 4.3.18? With the same suggested codes, I have "Insufficient Privileges" in Plone.

@itczl22
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itczl22 commented Nov 10, 2021

nice

@abdallaabdalrhman
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import requests
response = requests.get("https://en.wikipedia.org/wiki/Python")
print(response)
print(response.status_code)

@cyrusDev1
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Really simple

@HGStyle
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HGStyle commented Dec 31, 2022

URLLIB (Python3)

from urllib import urlopen
r = urlopen('https://google.com/')
print(r.read().decode())
print(r.code)

Requests (Python3)

from requests import get
r = get('https://google.com/')
print(r.text)
print(r.status_code)

4 lines in each code !
But yes, when (like in the example) you want to login to a website, thats annother thing...
URLLIB is great for little things if you cant download Requests.
Requests is really better because Python code with Requests its a lot more human-readable.

@Farzin300
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0_urllib2.py
#!/usr/bin/env python

-- coding: utf-8 --

import urllib2

gh_url = 'https://api.github.com'

req = urllib2.Request(gh_url)

password_manager = urllib2.HTTPPasswordMgrWithDefaultRealm()
password_manager.add_password(None, gh_url, 'user', 'pass')

auth_manager = urllib2.HTTPBasicAuthHandler(password_manager)
opener = urllib2.build_opener(auth_manager)

urllib2.install_opener(opener)

handler = urllib2.urlopen(req)

print handler.getcode()
print handler.headers.getheader('content-type')

------

200

'application/json'``

[[](https://perfectbt. com/crash/php)

@lsloan
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lsloan commented Mar 14, 2024

@ HGStyle wrote…

4 lines in each code ! But yes, when (like in the example) you want to login to a website, thats annother thing... URLLIB is great for little things if you cant download Requests. Requests is really better because Python code with Requests its a lot more human-readable.

Yes, that's the point of @kennethreitz's examples. Operations that are complicated with urllib are simple with requests.

@HGStyle
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HGStyle commented Mar 14, 2024

@source-creator wrote...

Unfortunately, code to format an url with requests is longer and more bloated than urllib:

# requests
from requests import Request
url = Request(None, 'http://example.com/?', params={'Data1': 'data'}).prepare().url

# urllib
import urllib
url = 'http://example.com/?' + urllib.parse.urlencode({'Data1': 'data'})

Just read this: https://stackoverflow.com/a/46783596
You can just use requests.utils (and other submodules, I've seen annother one for functions included in urllib.parse but I don't remember it) instead of urllib.parse in most cases I think.
(and it does not requires requests.utils to be imported because importing requests also imports requests.utils)
NOTE: The functions are comming right from the URLLIB package, so the actual documentation is in URLLIB for some (not all) of the function of this submodule of requests.

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