Created
June 15, 2019 06:19
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#!/bin/bash | |
# number of buckets | |
declare -i nB=6 | |
# values by key | |
declare -Ai Vk=( | |
[a]=3632376 | |
[b]=1403349 | |
[c]=1509800 | |
[d]=837855 | |
[e]=641015 | |
[f]=1270371 | |
[g]=485138 | |
[h]=1233635 | |
[i]=1990347 | |
[j]=253057 | |
[k]=223848 | |
[l]=707307 | |
[m]=1059271 | |
[n]=581775 | |
[o]=1794386 | |
[p]=1131515 | |
[q]=41518 | |
[r]=867451 | |
[s]=2095579 | |
[t]=3873869 | |
[u]=356153 | |
[v]=228228 | |
[w]=1569942 | |
[x]=10700 | |
[y]=139113 | |
[z]=27041 | |
) | |
# bare list of values | |
declare -a V=( "${Vk[@]}" ) # just the values | |
# number of values | |
declare -i nV=${#V[@]} | |
# sum of values (and of buckets) | |
declare -i S | |
for ((i=0;i<nV;++i)) do S+=V[i] ; done | |
# mean of values | |
declare -i Mv=S/nV | |
# mean per bucket | |
declare -i Mb=S/nB | |
# Resulting variance should be better than what you'd get by putting everything | |
# in one bucket... | |
declare -i BestV=S*Mb # == S*S/nB | |
declare -i i j p q v t | |
declare -a B=() | |
declare -ai T=() | |
declare -i Var | |
declare -a SortedA=( "${V[@]}" ) | |
# Sort nV items from V[] into SortedA[] | |
for ((i=0;i<nV;++i)) do | |
for((j=i+1;j<nV;++j)) do | |
(( SortedA[i] < SortedA[j] )) && t=${SortedA[i]} SortedA[i]=${SortedA[j]} SortedA[j]=$t | |
done | |
done | |
declare -i G=4 # gamma fuzz-convergence factor | |
printf 'Initial test variance=%s\n' $BestV | |
for ((z=0;z<100000;++z)) do | |
(( SECONDS != oSECONDS && ( oSECONDS = SECONDS ) )) && printf '%u \r' $z | |
B=() | |
Tb=() | |
if (( ( mode = 0 ) == 0 )) ; then | |
g=- | |
# Randomize order of nV items in V[] | |
for ((i=0;i<nV;++i)) do | |
((j=RANDOM%nV)) | |
t=${V[i]} V[i]=${V[j]} V[j]=$t | |
done | |
# Pack into nB buckets B[], and compute bucket totals into Tb[] | |
for ((i=0;i<nV;++i)) do | |
v=V[i] | |
# choose target bucket q | |
t=Tb[q=0] | |
for ((p=1;p<nB;++p)) do | |
((Tb[p]<t)) && (( t=Tb[q=p] )) | |
done | |
# add to bucket | |
((Tb[q]+=v)) | |
B[q]+="+$v" | |
done | |
else | |
# Pack nV items from SortedA[] into nB buckets B[], and compute bucket totals into Tb[] | |
(( g = RANDOM % (G-1) + 1 )) | |
for ((i=0;i<nV;++i)) do | |
v=V[i] | |
# choose target bucket q | |
(( q = RANDOM % ( nB * ( nV - i + 1 )**g / nV**g + 1 ) )) | |
# add to bucket | |
((Tb[q]+=v)) | |
B[q]+="+$v" | |
# re-sort nB buckets Tb[] & B[] | |
for (( p=q+1 ; p<nV && Tb[q] > Tb[p] ; ++p )) do :; done | |
if (( p>q+1 )) ; then | |
Tb=( "${Tb[@]:0:q}" "${Tb[@]:q+1:p-q-1}" "${Tb[@]:q:1}" "${Tb[@]:p}" ) | |
B=( "${B[@]:0:q}" "${B[@]:q+1:p-q-1}" "${B[@]:q:1}" "${B[@]:p}" ) | |
fi | |
done | |
fi | |
# Compute population variance between bucket totals. | |
# (Don't need squareroot for stddev, since they're only for comparison) | |
for (( Var=-Mb*Mb, p=0 ; p<nB ; ++p )) do | |
(( t=Tb[p], Var += t*t/nB )) | |
done | |
if ((Var >= 0 && Var < BestV)) ; then | |
((BestV=Var)) | |
BestT=( "${Tb[@]}" ) | |
BestO=( "${B[@]}" ) | |
# StdDev = √Var, using Newton's square-root method | |
for (( StdDev=3**${#Var} ; StdDev**2 > Var || (StdDev+1)**2 < Var ; StdDev+=Var/StdDev, StdDev /= 2 )) do :;done | |
printf 'Improved: mode=%s gamma=%s var=%s stddev=±%s µ/σ=%s\n' "$mode" "$g" "$Var" "$StdDev" "$((Mb/StdDev))" | |
for ((p=0;p<nB;++p)) do | |
printf '\t%s=%s\n' "${Tb[p]}" "${B[p]#'+'}" | |
done | |
fi | |
done |
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