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June 2, 2016 22:05
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The following snippet compiles under Swift 2.2, but not Swift 3. It defines a (quite useless) left shift operator on `Double` values. For some reason, Swift 3's type inference engine can go awry when such a shift operator is used in a subexpression.
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| public func <<(num: Double, exp: Int) -> Double { | |
| return num * Double(1 << exp) | |
| } | |
| let s = (0.5 << 5) - 1 | |
| print(s) |
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Are you sure that's a bug? It looks to me as if a bug were fixed not introduced