LCD Challange, read only part 1 first: https://github.com/Chase22/NumberToLcd/tree/82c73574f5a84a2c99a33a0e6fb3dc32d473efcb

part1.py

def num(n):
    string = ["", "", ""]
    for d in str(int(n)):
        for i, l in enumerate(digit(int(d)).split("\n")):
            string[i] += l
        # end for
    # end for
    return "\n".join(string)
# end def


def digit(n):
    string = " "
    string += "." if n in (1,4) else "_"
    string += " \n"
    
    string += "'" if n in (1,2,3,7) else "|"
    string += "." if n in (0,1,7) else "_"
    string += "'" if n in (5,6) else "|"
    string += "\n"
    
    string += "|" if n in (0,2,6,8) else "'"
    string += "." if n in (1,4,7) else "_"
    string += "'" if n in (2,) else "|"
    
    return string
# end def


for i in range(0,101):
    print(num(i), i)
# end for

part2.py

def num(n, width=1, height=1):
    string = [""] * (height + height + 3)
    for d in str(int(n)):
        for i, l in enumerate(digit(int(d), width, height).split("\n")):
            string[i] += l
        # end for
    # end for
    return "\n".join(string)
# end def


def digit(n, width=1, height=1):
    string = " " + (("." if n in (1,4) else "_") * width) + " \n"
    
    string += (("'" if n in (1,2,3,7) else "|") + (" "                             * width) + ("'" if n in (5,6) else "|") + "\n") * (height-1)
    string += ("'" if n in (1,2,3,7) else "|") + (("." if n in (0, 1, 7) else "_") * width) + ("'" if n in (5,6) else "|") + "\n"
    
    string += (("|" if n in (0,2,6,8) else "'") + (" "                           * width) + ("'" if n in (2,) else "|") + "\n") * (height-1)
    string += ("|" if n in (0,2,6,8) else "'") + (("." if n in (1,4,7) else "_") * width) + ("'" if n in (2,) else "|") + "\n"
    
    return string
# end def


for i in range(0,101):
    print(num(i, width=3, height=2), i)
# end for