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Check if the DOM node is visible in the viewport

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gistfile1.js
JavaScript
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function elementInViewport(el) {
var rect = el.getBoundingClientRect()
return rect.top < (window.innerHeight || document.body.clientHeight) && rect.left < (window.innerWidth || document.body.clientWidth);
}
// and then you can use it:
alert(elementInViewport(document.getElementById('inner')));
// or
alert(elementInViewport($('#inner')[0]));‚Äč
`

Forgot your semicolon after the variable declaration.

This fails if an element is above or to the left of the viewport. When rect.top or rect.left are negative, the respective clauses will still pass regardless of the values of rect.bottom or rect.right.

This is the code I use:

return (
    (boundingRect.top >= 0 ||
        boundingRect.bottom <= window.innerHeight) &&
    (boundingRect.left >= 0 ||
        boundingRect.right <= window.innerWidth)
);

Try this:

return rect.bottom > 0 &&
        rect.right > 0 &&
        rect.left < (window.innerWidth || document.documentElement.clientWidth) /*or $(window).width() */ &&
        rect.top < (window.innerHeight || document.documentElement.clientHeight) /*or $(window).height() */;

Both previous solutions have the algebra wrong. Think about it, the top of an element can be above the top of viewport, but if the bottom of the element is showing (i.e. is below the top of the viewport), then it is still visible. Likewise for horizontal calculations.

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