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Check if the DOM node is visible in the viewport
function elementInViewport(el) {
var rect = el.getBoundingClientRect()
return < (window.innerHeight || document.body.clientHeight) && rect.left < (window.innerWidth || document.body.clientWidth);
// and then you can use it:
// or
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ctbarna commented Feb 22, 2013

This fails if an element is above or to the left of the viewport. When or rect.left are negative, the respective clauses will still pass regardless of the values of rect.bottom or rect.right.

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ctbarna commented Feb 22, 2013

This is the code I use:

return (
    ( >= 0 ||
        boundingRect.bottom <= window.innerHeight) &&
    (boundingRect.left >= 0 ||
        boundingRect.right <= window.innerWidth)

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ucavus commented Apr 29, 2013

Try this:

return rect.bottom > 0 &&
        rect.right > 0 &&
        rect.left < (window.innerWidth || document.documentElement.clientWidth) /*or $(window).width() */ && < (window.innerHeight || document.documentElement.clientHeight) /*or $(window).height() */;

Both previous solutions have the algebra wrong. Think about it, the top of an element can be above the top of viewport, but if the bottom of the element is showing (i.e. is below the top of the viewport), then it is still visible. Likewise for horizontal calculations.

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