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@mbostock
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Line Transition
license: gpl-3.0

This example is the second of three in the Path Transitions tutorial; see the previous example for context.

The desired pairing of numbers for path interpolation is like this:

M x0, y0 L x1, y1 L x2, y2 L x3, y3 L xR, y4
   ↓   ↓    ↓   ↓    ↓   ↓    ↓   ↓
M xl, y0 L x0, y1 L x1, y2 L x2, y3 L x3, y4

Where xl is some negative value off the left side, and xr is some positive value off the right side. This way, the first point ⟨x0,y0⟩ is interpolated to ⟨xl,y0⟩; meaning, the x-coordinate is interpolated rather than the y-coordinate, and so the path appears to slide off to the left. Likewise, the incoming point ⟨xr,y4⟩ is interpolated to ⟨x3,y4⟩.

While you could write a custom interpolator and use transition.attrTween to achieve this, a much simpler solution is to interpolate the transform attribute rather than the path. This way, the shape of the path remains static while the it translates left during the transition.

Immediately prior to the transition, the path is redrawn as follows:

M x0, y0 L x1, y1 L x2, y2 L x3, y3 L xr, y4

Then, a transform transition is applied:

translate(0,0)
          ↓
translate(xl,0)

This causes the path to slide left. A clip path is used so the path is not visible outside of the chart body.

Note that for charts with spline interpolation, you’ll need to crop the visible part of the line by an extra point, so that the change in tangent is not visible; see the next example.

<!DOCTYPE html>
<meta charset="utf-8">
<style>
.line {
fill: none;
stroke: #000;
stroke-width: 1.5px;
}
</style>
<svg width="960" height="500"></svg>
<script src="//d3js.org/d3.v4.min.js"></script>
<script>
var n = 40,
random = d3.randomNormal(0, .2),
data = d3.range(n).map(random);
var svg = d3.select("svg"),
margin = {top: 20, right: 20, bottom: 20, left: 40},
width = +svg.attr("width") - margin.left - margin.right,
height = +svg.attr("height") - margin.top - margin.bottom,
g = svg.append("g").attr("transform", "translate(" + margin.left + "," + margin.top + ")");
var x = d3.scaleLinear()
.domain([0, n - 1])
.range([0, width]);
var y = d3.scaleLinear()
.domain([-1, 1])
.range([height, 0]);
var line = d3.line()
.x(function(d, i) { return x(i); })
.y(function(d, i) { return y(d); });
g.append("defs").append("clipPath")
.attr("id", "clip")
.append("rect")
.attr("width", width)
.attr("height", height);
g.append("g")
.attr("class", "axis axis--x")
.attr("transform", "translate(0," + y(0) + ")")
.call(d3.axisBottom(x));
g.append("g")
.attr("class", "axis axis--y")
.call(d3.axisLeft(y));
g.append("g")
.attr("clip-path", "url(#clip)")
.append("path")
.datum(data)
.attr("class", "line")
.transition()
.duration(500)
.ease(d3.easeLinear)
.on("start", tick);
function tick() {
// Push a new data point onto the back.
data.push(random());
// Redraw the line.
d3.select(this)
.attr("d", line)
.attr("transform", null);
// Slide it to the left.
d3.active(this)
.attr("transform", "translate(" + x(-1) + ",0)")
.transition()
.on("start", tick);
// Pop the old data point off the front.
data.shift();
}
</script>
@YaweiZhang-930
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@alexsmartens I am trying to build something similar in react-native as well. Did you get any chance to figure this out yet?

@NimChimpsky
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How can people use this knowing that the tick function is called by an exponentially number of growing of callees ? It will just grind user's cpu/browser into the ground.

@NimChimpsky
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.transition()
      .duration(500)
      .ease("linear")
      .attr("transform", "translate(" + x(-1) + ",0)")
      .each("end", tick);

.each(,) runs a new function "tick" for each point after each iteration, so it'll exponentially grow per cycle. I left this open on a second tab and it ran my CPU into the ground.

which therefore makes this example completely invalid without a significant refactoring, which everyone else seems to be happily ignoring ... I don't understand.

@nateblain
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@NimChimpsky I agree.

@thanhtschoepe
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thanhtschoepe commented Sep 3, 2021

I made a notebook using this example. Check it out. 😊. Please give me feedback if you have any.
https://observablehq.com/@ninjapupcodes/ping-chart

Thank you @mbostock for the amazing guide & @pepijnverburg for the duration 0 trick.

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