Created
April 5, 2017 08:28
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Python IBAN Checker
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# Based on http://codereview.stackexchange.com/questions/135366/python-iban-validation | |
import string | |
def is_iban(unchecked_iban): | |
LETTERS = {ord(d): str(i) for i, d in enumerate(string.digits + string.ascii_uppercase)} | |
def _number_iban(iban): | |
return (iban[4:] + iban[:4]).translate(LETTERS) | |
def generate_iban_check_digits(iban): | |
number_iban = _number_iban(iban[:2] + '00' + iban[4:]) | |
return '{:0>2}'.format(98 - (int(number_iban) % 97)) | |
def valid_iban(iban): | |
return int(_number_iban(iban)) % 97 == 1 | |
return generate_iban_check_digits(unchecked_iban) == unchecked_iban[2:4] and valid_iban(unchecked_iban) | |
def generate_valid_iban():
import random, string
def is_iban(unchecked_iban):
LETTERS = {ord(d): str(i) for i, d in enumerate(string.digits + string.ascii_uppercase)}
def _number_iban(iban):
return (iban[4:] + iban[:4]).translate(LETTERS)
def generate_iban_check_digits(iban):
number_iban = _number_iban(iban[:2] + '00' + iban[4:])
return '{:0>2}'.format(98 - (int(number_iban) % 97))
def valid_iban(iban):
return int(_number_iban(iban)) % 97 == 1
return generate_iban_check_digits(unchecked_iban) == unchecked_iban[2:4] and valid_iban(unchecked_iban)
def bank_ck(ktn):
ktn = list(map(lambda x: int(x), ktn))[::-1]
generator = [2, 3, 4, 5, 6, 7, 8, 9, 3]
rest = sum(map(lambda x: x[0] * x[1], zip(generator, ktn))) % 11
if rest == 1:
return 0
if rest == 0:
return 0
return 11 - rest
while True:
blz = "13050000"
ktnr = str(random.randint(111111111, 999999999))
ktnr = "{}{}".format(ktnr, bank_ck(ktnr))
iban = "DE{check}{blz}{ran}".format(check=random.randint(11, 99), blz=blz, ran=ktnr)
if is_iban(iban):
print(iban)
break
return iban
it doesn't account for valid ISO2 country names
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Generate a valid german IBAN