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February 21, 2019 15:06
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say we start with two linear functions | |
f(x) = a*x + b | |
g(x) = c*x + d | |
from previous work, we have their integrals (ignoring the offset) | |
F(x) = 1/2*a*x^2 + b*x | |
G(x) = 1/2*c*x^2 + d*x | |
now we compare the integral of the product of f(x)*g(x) | |
j(x) = [f(x)*g(x)]dx = 1/3*a*c*x^3 + 1/2*(b*c + a*d)*x^2 + b*d*x | |
with the (much easier to compute) derivative of the product of F(x)*G(x) | |
k(x) = (F(x)*G(X))' = a*c*x^3 + 3/2*(b*c + a*d)*x^2 + 2*b*d*x | |
when we compare the coefficients of j(x) and k(x) by division, we notice that they relate like this: | |
1/2 * (2*b*d) = b*d | |
1/3 * (3/2*(b*c + a*d)) = 1/2*(b*c + a*d) | |
1/3 * (a*c) = a*c |
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