9/26 HW: Different ways to...

different_ways.rb

# Let's go back to the exercise where we determined what is and isn't a vowel. With ruby, there's always more than one way to do something and get the same result.
# Assuming vowels a,e,i,o,u:
# Write a method that returns whether a given letter is a vowel, using if and elsif
def is_vow(letter)
  if letter == "a"
    true
  elsif letter == "e"
    true
  elsif letter == "i"
    true
  elsif letter == "o"
    true
  elsif letter == "u"
    true
  else
    false
  end
end

# Write a method that returns whether a given letter is a vowel, using case
def is_vow2(letter)
  case letter
  when "a", "e", "i", "o", "u"
    true
  else
    false
  end
end

# Write a method that returns whether a given letter is a vowel, using if with no else, all on a single line
def is_vow3(letter)
  true if letter.match(/[aeiou]/)
end

# Write a method that returns whether a given letter is a vowel without using if or case while all on a single line
def is_vow4(letter)
  letter == "a" || letter == "e" || letter == "i" || letter == "o" || letter == "u"
end

# Write a method that returns whether a given letter is a vowel without checking equality, or the use of if, using the array of vowels
# DOESN'T WORK:
def is_vow5(letter)
  ["a", "e", "i", "o", "u"].select do |vowel|
    vowel == letter
  end  
end

# Write a method that will evaluate a string and return the first vowel found in the string, if any
def first_vow6(str)
  puts str[str.index(/[aeiou]/)] if str.index(/[aeiou]/) != nil
end

# Write a method that will evaluate a string and return the ordinal position (index) of the string where the first vowel is found, if any
# DON'T KNOW WHAT AN ORDINAL POSITION IS
def first_vow7(str)
  str.index(/[aeiou]/).ord
end

# hint: remember that every line of ruby code has a return value, and that a method will return the result of the last operation