cronrun: run command with logging for crontab entries

README.md

cronrun : run command in cron

I often have errors where running a command from cron wasn't the same as running it from the command line. This is a small/silly attempt to remove those descrepencies and be able to just copy and paste what was in cron and expect that is the same.

I just put cronrun in /usr/local/bin and set it executable, and then set PATH in my crontab to include /usr/local/bin.

cronrun basically does:

• set any environment i want (add ~/bin to path)

• support '--logname=yourlog.log' and redirect output there so you don't have to read mail

• support --logname=foo-YYYYMMDD.log replacing with current date.

• execute the command provided.

   $ crontab -l
   PATH=/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin
   03 0-23/2 * * * cronrun --quiet --logname=my-command.log my-command my-args
  

cronrun

#!/bin/sh
# https://gist.github.com/smoser/ee1687c231f5a125669374ac0a732a45

export PATH=$HOME/bin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin
[ "$1" = "--quiet" ] && shift && quiet=true || quiet=false

if [ "${1%=*}" = "--logname" ]; then
   LOGDIR=${LOGDIR:-$HOME/cronlogs}
   lname_in=${1#*=}
   # replace YYYYMMDD with the date formated in that way.
   yyyymmdd=$(date +%Y%m%d)
   logname=$(echo "$lname_in" | sed "s/YYYYMMDD/${yyyymmdd}/")
   shift

   ldir=${LOGDIR}/
   [ "${logname#/}" = "${logname}" ] || ldir=""

   if [ "${lname_in}" = "${logname}" ]; then
      lfile=${ldir}${logname}
      $quiet || echo "# $@" >> "${lfile}"
   else
      [ -z "${ldir}" -o -d "${ldir}" ] || mkdir "${ldir}"
      lfile="${ldir}${logname}"
      i=0;
      while lfile="${ldir}${logname}.${i}.log" && [ -e "${lfile}" ]; do
         i=$((${i}+1))
      done
   fi
   exec >>"$lfile" 2>&1
fi
exec "$@"