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December 11, 2023 02:16
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Infinite periodic continued fractions
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def periodic(L: list): | |
"""Return an infinite periodic continued fraction representation.""" | |
# Create a copy of the list and append it to itself. | |
# This creates an "infinite" list of the form [a0, ..., an, [a0, ..., an, [a0, ..., an, ...]]] | |
# The list is not actually infinite, it only has length n+1! It has infinite depth and finite length 🤯 | |
S = list(L) | |
S.append(S) | |
return S | |
# EXAMPLES: | |
# Periodic continued fraction representation of golden ratio | |
golden_ratio = periodic([1]) | |
# Periodic continued fraction representation of sqrt(2) | |
sqrt2 = [1, periodic([2])] | |
def convergents(continued_fraction, h=(0, 1), k=(1, 0)): | |
"""Yield the convergents of a continued fraction.""" | |
if isinstance(continued_fraction, list): | |
N = len(continued_fraction) - 1 | |
for i in range(N): | |
a_i = continued_fraction[i] | |
h_i, k_i = h[0] + a_i*h[1], k[0] + a_i*k[1] | |
yield h_i, k_i | |
h, k = (h[1], h_i), (k[1], k_i) | |
yield from convergents(continued_fraction[N], h, k) | |
else: | |
a_n = continued_fraction | |
h_n, k_n = h[0] + a_n*h[1], k[0] + a_n*k[1] | |
yield h_n, k_n | |
# EXAMPLES: | |
# Import islice to slice the convergents iterator. | |
from itertools import islice | |
# Print the first 10 convergents of the golden ratio | |
print('First 10 convergents of the golden ratio:') | |
for i, (h, k) in enumerate(islice(convergents(golden_ratio), 10), start=1): | |
print(f"{i}: {h, k}, {h/k}") | |
# First 10 convergents of the golden ratio: | |
# 1: (1, 1), 1.0 | |
# 2: (2, 1), 2.0 | |
# 3: (3, 2), 1.5 | |
# 4: (5, 3), 1.6666666666666667 | |
# 5: (8, 5), 1.6 | |
# 6: (13, 8), 1.625 | |
# 7: (21, 13), 1.6153846153846154 | |
# 8: (34, 21), 1.619047619047619 | |
# 9: (55, 34), 1.6176470588235294 | |
# 10: (89, 55), 1.6181818181818182 | |
print() | |
# Print the first 10 convergents of sqrt(2) | |
print('First 10 convergents of sqrt(2):') | |
for i, (h, k) in enumerate(islice(convergents(sqrt2), 10), start=1): | |
print(f"{i}: {h, k}, {h/k}") | |
# First 10 convergents of sqrt(2): | |
# 1: (1, 1), 1.0 | |
# 2: (3, 2), 1.5 | |
# 3: (7, 5), 1.4 | |
# 4: (17, 12), 1.4166666666666667 | |
# 5: (41, 29), 1.4137931034482758 | |
# 6: (99, 70), 1.4142857142857144 | |
# 7: (239, 169), 1.4142011834319526 | |
# 8: (577, 408), 1.4142156862745099 | |
# 9: (1393, 985), 1.4142131979695431 | |
# 10: (3363, 2378), 1.4142136248948696 |
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