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@spiralx
Last active December 15, 2016 23:37
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Gulp - suspend watcher during task execution
var gulp = require('gulp');
function doGitCheckout(callback) {
console.log('doing checkout...');
setTimeout(function() {
console.log('done checkout...');
callback();
}, 1000);
}
var watcher;
gulp.task('watch:start', function() {
if (!watcher) {
watcher = gulp.watch('dist/**/*', ['build']);
console.log('started watcher');
}
});
gulp.task('watch:stop', function() {
if (watcher) {
watcher.end();
watcher = null;
console.log('stopped watcher');
}
});
gulp.task('git:checkout', ['watch:stop'], function(cb) {
console.log('isWatching = ' + !!watcher);
// Start the Git checkout...
doGitCheckout(function() {
// The Git checkout is finished!
gulp.start('watch:start', function() {
cb();
});
});
});
gulp.task('default', ['watch:start', 'git:checkout']);
@davidrenne
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This looked promising for my use case, but my use case uses gulp.watch() which is a long running process and I tried tweaking this example to stop my process and it only seemed to work once no matter what I did. Oh well I found another solution to get my process to not fight with gulp running and killing processes when it detected file changes.

@kevinbeal
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@davidrenne What was the other solution? This solution doesn't work for me either.

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