Skip to content

Instantly share code, notes, and snippets.

@tbranyen
Created September 22, 2011 16:51
Show Gist options
  • Star 21 You must be signed in to star a gist
  • Fork 3 You must be signed in to fork a gist
  • Save tbranyen/1235317 to your computer and use it in GitHub Desktop.
Save tbranyen/1235317 to your computer and use it in GitHub Desktop.
backbone.js sub routing
/* Pretend app setup stuff is here */
/* Kick off app */
jQuery(function($) {
var Gallery = app.module("gallery");
app.Router = Backbone.Router.extend({
initialize: function() {
this.gallery = new Gallery.Router("gallery/");
}
});
// Actually initialize
new app.Router();
});
(function(Helper) {
Helper.SubRoute = Backbone.Router.extend({
constructor: function(prefix) {
var routes = {};
// Prefix is optional, set to empty string if not passed
prefix = prefix || "";
// Allow for optionally omitting trailing /. Since base routes do not
// trigger with a trailing / this is actually kind of important =)
if (prefix[prefix.length-1] == "/") {
prefix = prefix.slice(0, prefix.length-1);
// If a prefix exists, add a trailing /
} else if (prefix) {
prefix += "/";
}
// Every route needs to be prefixed
_.each(this.routes, function(callback, path) {
if (path) {
return routes[prefix + path] = callback;
}
// If the path is "" just set to prefix, this is to comply
// with how Backbone expects base paths to look gallery vs gallery/
routes[prefix] = callback;
});
// Must override with prefixed routes
this.routes = routes;
// Required to have Backbone set up routes
Backbone.Router.prototype.constructor.call(this);
}
});
})(app.module("helper"));
@jessebeach
Copy link

WAH-WAH. Let us know what you find.

@carpeliam
Copy link

I ended up logging an issue against @geekdave's repo at BackboneSubroute/backbone.subroute#4 - I'm not 100% sure everything is correct (it's a little handwavy, I'm under pressure to get something out the door blahblahblah so I had to move on), but I think that's the gist of things. Hopefully I'll have time to come back to it, if @geekdave isn't able to get to the bottom of it himself.

@SamDecrock
Copy link

And how to dynamically remove the subroute?

@Daveawb
Copy link

Daveawb commented Jun 24, 2014

@SamDecrock you can't without manipulating Backbone.history and allowing your application to have knowledge of all the paths that were added. This can be quite a complex procedure if you haven't built your application with an ability to get paths from individual subroutes. I tend to create wrapping objects that have an activate and deactivate method that are managed by a facade to a Backbone router.

considering that you have a list of paths (allRoutes in this example).

for (var path in allRoutes) {
    var combinedPath = routerPrefix + '/' + path;

    // This removes all trace of the routes from the history
    Backbone.history.handlers = _.reject(
        Backbone.history.handlers, function(value) {
            return String.prototype.search.call(
                value.route, 
                combinedPath
            ) !== -1;
        }
    );
}

// Unfortunately, we still have a route in the history for the routerPrefix 
// (in fact we should have two, the one used by the primary router and
// one created by the sub router (the latter takes precedence as it has 
// been unshifted onto the handlers array. The next step therefore is to 
// get all the primary routes registered in the history.
var primaryHandlers = _.filter(Backbone.history.handlers, function(value) {
    return String.prototype.search.call(value.route, routerPrefix) !== -1;
});

// If the result has a length greater than 1 (this will be the case most of
// the time) then we need to remove the first one that was registered by 
// the subrouter, this leaves the primary route still available to start the 
// sub router again when it is needed. Else we want to keep the route as
// it was set by the primary router.
if (primaryHandlers.length > 1) {
    Backbone.history.handlers.splice(
        Backbone.history.handlers.indexOf(primaryHandlers[0])
    , 1);
}

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment