The following is an exercise in refactoring to remove code duplication. The implementation language is Scala. How would you solve it?

RefactoringPuzzle.scala

object RefactorPuzzle {
  case class IntRdr[+A](read: Int => A) {
    def map[B](f: A => B): IntRdr[B] = 
      IntRdr(f compose read)

    def flatMap[B](f: A => IntRdr[B]): IntRdr[B] =
      IntRdr(n => f(read(n)).read(n))
  }

  object IntRdr {
    def apply[A](a: A): IntRdr[A] =
      IntRdr(_ => a)
  }

  // Return all the Some values, or None if not all are Some.
  def runOptions[A](x: List[Option[A]]): Option[List[A]] = 
    x.foldRight[Option[List[A]]](Option(Nil))((a, b) => a.flatMap(aa => b.map(aa :: _)))

  // Apply an Int to a list of int readers and return the list of return values.
  def runIntRdrs[A](x: List[IntRdr[A]]): IntRdr[List[A]] = 
    x.foldRight[IntRdr[List[A]]](IntRdr(Nil))((a, b) => a.flatMap(aa => b.map(aa :: _)))

/*

========================
 THE REFACTORING PUZZLE
========================

The two functions `runOptions` and `runIntRdrs` share a lot of duplicated code.
This is demonstrated below.

How to refactor this code to remove the code duplication?

*/

//-------      -------------      -------      -----------
//def runOptions[A](x: List[Option[A]]): Option[List[A]] =
//def runIntRdrs[A](x: List[IntRdr[A]]): IntRdr[List[A]] =

//  ------------      -----------      ------------------------------------------------- 
//  x.foldRight[Option[List[A]]](Option(Nil))((a, b) => a.flatMap(aa => b.map(aa :: _)))
//  x.foldRight[IntRdr[List[A]]](IntRdr(Nil))((a, b) => a.flatMap(aa => b.map(aa :: _)))

}