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Keybase proof

I hereby claim:

  • I am c633 on github.
  • I am pqcrypt (https://keybase.io/pqcrypt) on keybase.
  • I have a public key whose fingerprint is E743 F730 678B B0C7 6777 72FE 049A D8DF E5EA 1AFC

To claim this, I am signing this object:

@vqhuy
vqhuy / docker-cleanup-resources.md
Created July 20, 2017 05:43 — forked from bastman/docker-cleanup-resources.md
docker cleanup guide: containers, images, volumes, networks

Docker - How to cleanup (unused) resources

Once in a while, you may need to cleanup resources (containers, volumes, images, networks) ...

delete volumes

// see: https://github.com/chadoe/docker-cleanup-volumes

$ docker volume rm $(docker volume ls -qf dangling=true)

$ docker volume ls -qf dangling=true | xargs -r docker volume rm

@vqhuy
vqhuy / resources.md
Created April 18, 2017 13:51 — forked from iam1980/resources.md
Shadow Brokers EQGRP Lost in Translation resources
@vqhuy
vqhuy / iMessage.md
Created May 28, 2016 05:53 — forked from anonymous/iMessage.md
Apple iMessage - Deficient by Design

Apple iMessage – Deficient by Design


Apple iMessage uses MAC-less encryption with malleable ciphertext. That, however, is not the worst part, and neither are the small 1280-bit RSA keys.

The worst part is that iMessage uses an independent ECDSA signature key, which is not only "independent" due to being a separate/different key from the AES encryption key, but also due to not being involved in the encryption/decryption stage at all!

dodgetocat_v2 (source)

@vqhuy
vqhuy / re100-svattt2015-solver.py
Last active August 3, 2016 16:24
re100 - SVATTT 2015
#!/usr/bin/env python
from z3 import *
def display_model(m):
block = {}
for x in m:
if 'b' in str(x):
block[ord(str(x)[-1:])] = int(str(m[x]))
@vqhuy
vqhuy / rsa-blind-signature.py
Created March 3, 2016 09:56
demo of RSA blind signature attack
#!/usr/bin/env sage -python2
from sage.all import *
e1 = long(599703852157208324988436697659896404638315905290324375700570316485421693)
e2 = long(2021187385200166516022746434619391941987919206967476592818217288363509)
print 'gcd(e1, e2) = ' + str(gcd(e1, e2)) # should be 1
n = long(108039548283467910018636019706918049787296862983920390620425680109149061265582938100265640505395436176923520902062289606379329490555998996693285930619495040456388113166495283026905991110314710632437395833112529488024010984327573108928719840003018232385552027586272040584786259207191357206321725581066222359269709853312236804681275337051689984480610347322381805920314518020927280061535012383180989715215061621017100281215170089223279840979641688194933238176625422507335413025975742216947757245112001827202742177202602339368271393570814426349)
@vqhuy
vqhuy / crypto4000-solver.py
Last active August 3, 2016 16:25
crypto 4000 solver - SV ATTT 2015
'''
./hash_extender --data VVNFUk5BTUU9YWRtaW4AQmlvZ3JhcGh5PWFkbWkAUk9MRT0w --secret 16 --append AFJPTEU9MQ== --signature 89542f421e21de8edfcf39ec0e88b29b --format md5
Type: md5
Secret length: 16
New signature: 8c8a2d7f702abae1fb78766aa8694ebd
New string: 56564e46556b3542545555395957527461573441516d6c765a334a68634768355057466b62576b41556b394d525430778000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000200000000000041464a50544555394d513d3d
'''
from pwn import *
s = remote("192.168.1.101", 31330)
@vqhuy
vqhuy / re300-solver.c
Created November 6, 2015 18:07
re300 - SVATTT 2015 CTF
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdint.h>
int dword_804B16C, dword_804B170, dword_804B174, dword_804B178, dword_804B17C, dword_804B180;
int pos = 0;
int v11;
int v12;
@vqhuy
vqhuy / crackme.c
Last active August 3, 2016 16:26 — forked from TylerOderkirk/crackme.c
A demonstration of Markus Gaasedelen's method for reversing a binary - see URL in find_password.py
#include <stdlib.h>
#include <stdio.h>
void main(int argc, char *argv[])
{
if( argv[1][0] == 'f' ) {
if( argv[1][1] == 'o' ) {
if( argv[1][2] == 'o' ) {
if( argv[1][3] == '\x00' ) {
printf( "good password\n" );
@vqhuy
vqhuy / rol-ror.py
Created August 13, 2015 06:15
python rol, ror operation implement
###########################################################################
# Rotating bits (tested with Python 2.7)
from __future__ import print_function # PEP 3105
# max bits > 0 == width of the value in bits (e.g., int_16 -> 16)
# Rotate left: 0b1001 --> 0b0011
rol = lambda val, r_bits, max_bits: \
(val << r_bits%max_bits) & (2**max_bits-1) | \