#!/usr/bin/env bash
while [ 1 ]; do
# The --password-store=basic is there to avoid the KDE Wallet access
# request dialog on start-up.
google-chrome --password-store=basic --app=,150.619812\&z=10 &
# Get the process ID, so we can kill it later
sleep 3
# Get the X window ID of the process we just started so we can resize it.
. /etc/rc.conf
. /etc/rc.d/functions
. /etc/conf.d/virtuoso
# The semaphore alphabet.
# The first character represents number of flags held straight up, and so on, going clockwise.
# Info taken from:
alpha = {
'00002000': ' ',
'10100000': '#',
'00001100': 'A',
'00001010': 'B',
'00001001': 'C',
'10001000': 'D',
View bulkloader.vsql
drop table load_list;
create table load_list (
ll_file varchar,
ll_graph varchar,
ll_state int default 0, -- 0 not started, 1 going, 2 done
ll_started datetime,
ll_done datetime,
ll_host int,
ll_work_time integer,
ll_error varchar,
My answer was: "1 vowel; 3-5 digits; letters in ascending order, but sequence
can restart after first 2 if rest of letters are unique. #googlenexus #pattern"
Though it may seem a bit iffy, this is the most specific pattern I could find
that would validate all strings marked as "yes" and invalidate all strings
marked as "no". After 5 hours, I'm not prepared to explore this puzzle any
The following code verifies that my solution holds true.
#!/usr/bin/env python
Use pip to get a list of local packages to check against one or more package
indexes for updated versions.
import pip
import sys, xmlrpclib
from cStringIO import StringIO
from distutils.version import StrictVersion, LooseVersion
from subprocess import Popen, PIPE