Remove all from Docker

remove-all-from-docker.sh

# Stop all containers
docker stop `docker ps -qa`

# Remove all containers
docker rm `docker ps -qa`

# Remove all images
docker rmi -f `docker images -qa `

# Remove all volumes
docker volume rm $(docker volume ls -qf)

# Remove all networks
docker network rm `docker network ls -q`

# Your installation should now be all fresh and clean.

# The following commands should not output any items:
# docker ps -a
# docker images -a 
# docker volume ls

# The following command show only show the default networks:
# docker network ls

<3

this is awesome lol

nice

the "f" parameter in docker volume rm $(docker volume ls -qf) is for filter. if you don't specify it, it'll raise an error. But it's safe to ommit the f parameter, or here is the list of available filters:

• dangling (boolean - true or false, 0 or 1)
• driver (a volume driver’s name)
• label (label= or label==)
• name (a volume’s name)

Example:
docker volume rm $(docker volume ls -qf dangling="true")

@samhk222 docker volume rm $(docker volume ls -qf dangling="true") works perfectly! Thanks a lot!

Oneliner

docker stop `docker ps -qa` && docker rm `docker ps -qa` && docker rmi -f `docker images -qa ` && docker volume rm $(docker volume ls -qf) && docker network rm `docker network ls -q`

Better and more destructive oneliner

docker stop $(docker ps -qa); docker rm $(docker ps -qa); docker rmi -f $(docker images -qa); docker volume rm $(docker volume ls -q); docker network rm $(docker network ls -q)

<3 you save me. Thank you

thnx !! 😃

Shell scripts are damn ugly. But shell is so powerful 🙃
Why is rm -rf --all not in the docker binary lol...
Sigh, another try which does the same, but outputs less noise and adds a bit of sugar :

echo "Removing containers :" && if [ -n "$(docker container ls -aq)" ]; then docker container stop $(docker container ls -aq); docker container rm $(docker container ls -aq); fi; echo "Removing images :" && if [ -n "$(docker images -aq)" ]; then docker rmi -f $(docker images -aq); fi; echo "Removing volumes :" && if [ -n "$(docker volume ls -q)" ]; then docker volume rm $(docker volume ls -q); fi; echo "Removing networks :" && if [ -n "$(docker network ls | awk '{print $1" "$2}' | grep -v 'ID\|bridge\|host\|none' | awk '{print $1}')" ]; then docker network rm $(docker network ls | awk '{print $1" "$2}' | grep -v 'ID\|bridge\|host\|none' | awk '{print $1}'); fi;

Readable bash script at https://gist.github.com/Maxzor/6a3ca2c5c1c28af583711abc8e5fda01

Pre-defined network(bridge host none) can be ignored.

docker network rm `docker network ls -q --filter type=custom`

This will get rid of the following error message:

Error response from daemon: bridge is a pre-defined network and cannot be removed
Error response from daemon: host is a pre-defined network and cannot be removed
Error response from daemon: none is a pre-defined network and cannot be removed

Oneliner

docker stop `docker ps -qa` && docker rm `docker ps -qa` && docker rmi -f `docker images -qa ` && docker volume rm $(docker volume ls -qf) && docker network rm `docker network ls -q`

In this case I'd personally replace the '&&' with a ';' so they all run and in series or even a single '&' to run parallel. You don't want to to stop deleting the rest if one list returns nothing. Example, say there are no volumes, this will fail at that step and not delete the networks. && is mostly useful if the next command is predicated on the previous command having completed successful.

Fastest Method:

docker stop `docker ps -qa` ; docker rm `docker ps -qa` & docker rmi -f `docker images -qa ` & docker volume rm $(docker volume ls -qf) & docker network rm `docker network ls -q`

Oneliner

docker stop `docker ps -qa` && docker rm `docker ps -qa` && docker rmi -f `docker images -qa ` && docker volume rm $(docker volume ls -qf) && docker network rm `docker network ls -q`

In this case I'd personally replace the '&&' with a ';' so they all run and in series or even a single '&' to run parallel. You don't want to to stop deleting the rest if one list returns nothing. Example, say there are no volumes, this will fail at that step and not delete the networks. && is mostly useful if the next command is predicated on the previous command having completed successful.

Fastest Method:

docker stop `docker ps -qa` ; docker rm `docker ps -qa` & docker rmi -f `docker images -qa ` & docker volume rm $(docker volume ls -qf) & docker network rm `docker network ls -q`

Somebody already did it
https://gist.github.com/beeman/aca41f3ebd2bf5efbd9d7fef09eac54d#gistcomment-3362258

Try this 👍

docker stop `docker ps -qa`
docker system prune --volumes --all

You have a typo, it should be:

docker system prune --volumes --all (note plural volumes)

Try this 👍

docker stop `docker ps -qa`
docker system prune --volume --all

Thanks 😅
I just type without testing in a terminal.

You have a typo, it should be:

docker system prune --volumes --all (note plural volumes)

Try this +1

docker stop `docker ps -qa`
docker system prune --volume --all

BTW, it appears for me that the command above to delete Docker volumes is outdated; I get an error:

docker volume ls -qf
flag needs an argument: 'f' in -f
See 'docker volume ls --help'.

The command is now docker volume ls -q, I think. Here is my docker version:

 docker --version
Docker version 20.10.2, build 2291f61

I recommend:

docker stop $(docker ps -qa); docker rm $(docker ps -qa); docker rmi -f $(docker images -qa); docker volume rm $(docker volume ls -q); docker network rm $(docker network ls -q)

Here's a script that doesn't generate any errors, including if there are no containers/images/volumes/networks:

#!/bin/bash

echo "Listing containers..."
containers=$(docker ps -qa)
echo "containers: $containers"

if [ ! -z "$containers" ]
then
    echo "Stopping containers..."
    docker stop $containers
    echo "Removing containers..."
    docker rm $containers
else
    echo "No containers found"
fi

echo "Listing images..."
images=$(docker images -qa)
echo "images: $images"

if [ ! -z "$images" ]
then
    echo "Removing images..."
    docker rmi -f $images
else
    echo "No images found"
fi

echo "Listing volumes..."
volumes=$(docker volume ls -q)
echo "volumes: $volumes"

if [ ! -z "$volumes" ]
then
    echo "Removing volumes..."
    docker volume rm $volumes
else
    echo "No volumes found"
fi

echo "Listing networks..."
networks=$(docker network ls -q)
echo "networks: $networks"

if [ ! -z "$networks" ]
then
    echo "Removing networks..."
    docker network rm $networks
else
    echo "No networks found"
fi

echo "These should not output any items:"
docker ps -a
docker images -a 
docker volume ls

echo "This should only show the default networks:"
docker network ls

docker stop $(docker ps -qa)
docker system prune -a

that's all you need to remove everything

Hey this line $(...) doesn't work with fish. Is there an alternative that works everywhere?

Just drop the $, at least for that bit of fish. Or just run bash and then paste in the command.

Here's the fish version for clarity.

docker stop (docker ps -qa);
docker rm (docker ps -qa);
docker rmi -f (docker images -qa);
docker volume rm (docker volume ls -q);
docker network rm (docker network ls -q);

Hi, I tried docker volume rm $(docker volume ls -qf) to remove volumes but got the following message returned:

`flag needs an argument: 'f' in -f
See 'docker volume ls --help'.
"docker volume rm" requires at least 1 argument.
See 'docker volume rm --help'.

Usage: docker volume rm [OPTIONS] VOLUME [VOLUME...]

Remove one or more volumes`

I tried this instead and successfully removed all volumes:
docker volume rm $(docker volume ls -q)

After these commands I still had volumes under docker volume ls had to run docker volume prune to remove them. Reclaimed almost half a gig!

thanks

You have a typo, it should be:

docker system prune --volumes --all (note plural volumes)

Try this 👍

docker stop `docker ps -qa`
docker system prune --volume --all

This is actually plural now --volumes

thanks!!!

Thanks

<3

This is missing:

docker builder prune