While messing with a CF-U1 handheld PC that I bought off ebay I managed to mess up the BIOS and it
seems it reverted to previous settings which included an unknown BIOS password, it would however still
boot into windows. Since I could still boot windows I was able to dump the bios flash using
AFUWINGUI.EXE the version I used was 3.09.03.1462 which is available here:
https://ami.com/en/?Aptio_4_AMI_Firmware_Update_Utility.zip
There may be a more appropriate version to use as this seemed to have trouble checking the bios version when flashing but did work if you selected "Do Not Check ROM ID" but flashing isnt needed to get the password.
Run AFUWINGUI.EXE and at the bottom of the "Information" tab click the save button to make a backup of
your bios, the default name is afuwin.rom Now open this saved image with UEFITool_NE available here:
https://github.com/LongSoft/UEFITool/releases
I used UEFITool_NE_A51_win32.zip later versions should work fine. The new engine (NE) verson seems to deal with AMI's odd nvram format better.
Expand the first EfiFirmwareFilesystemGuid >> NVRAM dropdown tree and look for the GUID
C811FA38-42C8-4579-A9BB-60E94EDDFB34 (AMITSESetup)
with subtype Data there will be others with subtype Link which are older no longer valid entrys because
of the odd way AMI nvram works, if you find one of these right click on it and select "Go to data" and
it will take you to the actual data entry.
Now right click and select "Body hex view" and you should see something like:
0000 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
0010 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
0020 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
0030 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
0040 7B 13 94 A6 07 3A 29 CD D2 60 1A F4 5C 87 ED 1A {.”¦.:)ÍÒ`.ô\‡í.
0050 07 AE AE 41 DC D4 0A 68 AB FB FA 0E 55 A2 B0 35 .®®AÜÔ.h«ûú.U¢°5
0060 0B C9 66 5C C1 EF 1C 83 77 16 D2 A9 2D 3D 88 D0 .Éf\Áï.ƒw.Ò©-=ˆÐ
0070 E3 63 3E F7 99 8A F4 1D 4F B1 AA 44 05 D8 60 6B ãc>÷™Šô.O±ªD.Ø`k
0080 01
In this the bytes from 0x00 to 0x3F are the currently unset user password, 0x40 to 0x7F are the obfuscated administrator password and 0x80 is the quiet boot flag.
The password is obfuscated using super secure xor
VOID PasswordEncode( CHAR16 *Password, UINTN MaxSize)
{
UINTN ii;
unsigned int key = 0x935b;
#if SETUP_PASSWORD_NON_CASE_SENSITIVE
for ( ii = 0; ii < MaxSize; ii++ )
Password[ii] = ((Password[ii]>=L'a')&&(Password[ii]<=L'z'))?(Password[ii]+L'A'-L'a'):Password[ii];
#endif
// Encode the password..
for ( ii = 1; ii <= MaxSize/2; ii++ )
Password[ii-1] = (CHAR16)(Password[ii-1] ^ (key*ii));
}
So Xoring the above encoded password:
7B 13 94 A6 07 3A 29 CD D2 60 1A F4 5C 87 ED 1A 07 AE AE 41 DC D4 0A 68 AB FB FA 0E 55 A2 B0 35
0B C9 66 5C C1 EF 1C 83 77 16 D2 A9 2D 3D 88 D0 E3 63 3E F7 99 8A F4 1D 4F B1 AA 44 05 D8 60 6B
with
5B 93 B6 26 11 BA 6C 4D C7 E0 22 74 7D 07 D8 9A 33 2E 8E C1 E9 54 44 E8 9F 7B FA 0E 55 A2 B0 35
0B C9 66 5C C1 EF 1C 83 77 16 D2 A9 2D 3D 88 D0 E3 63 3E F7 99 8A F4 1D 4F B1 AA 44 05 D8 60 6B
gives
20 80 22 80 16 80 45 80 15 80 38 80 21 80 35 80 34 80 20 80 35 80 4e 80 34 80 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
Each character of the password is stored as 2 bytes, and as x86 is wrong endian im guessing should be read as 0x8020 0x8022 I have no idea where the 0x80 comes from possibly its something to do with the EFI_SHIFT_STATE_VALID in this case the password was lower case, possibly uppercase status is encoded in this byte too I have no idea I havent tested uppercase passwords.
From the unobfuscated data you can see the password is 13 characters long, im going to ignore the 0x80
bytes as i dont understand them :P and just look at the others:
20 22 16 45 15 38 21 35 34 20 35 4e 34
They appear to be some sort of scancodes, although while googleing this I found some AMI bioses seem
to use ascii here so you can read it out directly as text, but not on this machine.
When this CF-U1 arrived from ebay it had a password which i sucessfully guessed as "toughbook" my
second guess would have been "panasonic" since using text written on the front of the PC as a password
saves writing it under the battery cover :P
Looking through the older link entrys for the AMITSESetup nvram I found what I thought was the data
for this password which deobfuscating as above gave (ignoring the 0x80):
35 39 37 24 25 14 39 39 27
t o u g h b o o k
This seemed promising repeated characters have the same value and gives a bit of a key to the mapping
Some googeling later about UEFI scancodes and i found this page:
http://wiki.phoenix.com/wiki/index.php/EFI_KEY
From this it seems the value is the offset into this enum so in the toughbook example 35 translates to
EfiKeyD5 a second page I found gave the mapping from EfiKey to ascii:
https://github.com/tianocore/edk2/blob/master/MdeModulePkg/Bus/Usb/UsbKbDxe/KeyBoard.c#L36
So i made up a list of byte to ascii using these, below are just 0x10 to 0x4E to cover most values but not be too stupidly long.
Hex | Char | EFIkey | Hex | Char | EFIkey |
---|---|---|---|---|---|
10 | z | EfiKeyB1 | 30 | Tab | EfiKeyTab |
11 | x | EfiKeyB2 | 31 | q | EfiKeyD1 |
12 | c | EfiKeyB3 | 32 | w | EfiKeyD2 |
13 | v | EfiKeyB4 | 33 | e | EfiKeyD3 |
14 | b | EfiKeyB5 | 34 | r | EfiKeyD4 |
15 | n | EfiKeyB6 | 35 | t | EfiKeyD5 |
16 | m | EfiKeyB7 | 36 | y | EfiKeyD6 |
17 | , | EfiKeyB8 | 37 | u | EfiKeyD7 |
18 | . | EfiKeyB9 | 38 | i | EfiKeyD8 |
19 | / | EfiKeyB10 | 39 | o | EfiKeyD9 |
1A | EfiKeyRShift | 3A | p | EfiKeyD10 | |
1B | EfiKeyUpArrow | 3B | [ | EfiKeyD11 | |
1C | 1 | EfiKeyOne | 3C | ] | EfiKeyD12 |
1D | 2 | EfiKeyTwo | 3D | \ | EfiKeyD13 |
1E | 3 | EfiKeyThree | 3E | EfiKeyDel | |
1F | EfiKeyCapsLock | 3F | EfiKeyEnd | ||
20 | a | EfiKeyC1 | 40 | EfiKeyPgDn | |
21 | s | EfiKeyC2 | 41 | 7 | EfiKeySeven |
22 | d | EfiKeyC3 | 42 | 8 | EfiKeyEight |
23 | f | EfiKeyC4 | 43 | 9 | EfiKeyNine |
24 | g | EfiKeyC5 | 44 | ` | EfiKeyE0 |
25 | h | EfiKeyC6 | 45 | 1 | EfiKeyE1 |
26 | j | EfiKeyC7 | 46 | 2 | EfiKeyE2 |
27 | k | EfiKeyC8 | 47 | 3 | EfiKeyE3 |
28 | l | EfiKeyC9 | 48 | 4 | EfiKeyE4 |
29 | ; | EfiKeyC10 | 49 | 5 | EfiKeyE5 |
2A | ' | EfiKeyC11 | 4A | 6 | EfiKeyE6 |
2B | | | EfiKeyC12 | 4B | 7 | EfiKeyE7 |
2C | 4 | EfiKeyFour | 4C | 8 | EfiKeyE8 |
2D | 5 | EfiKeyFive | 4D | 9 | EfiKeyE9 |
2E | 6 | EfiKeySix | 4E | 0 | EfiKeyE10 |
2F | + | EfiKeyPlus |
Using the above list and the recovered scancodes gave:
20 22 16 45 15 38 21 35 34 20 35 4e 34
a d m 1 n i s t r a t 0 r
and when i tried adm1nistrat0r it worked!
This is not complete as there are still questions about the 0x80 bytes but my guess is they encode
the shift alt etc modifier keys but im back into my handheld so i'm not sure ill look further into it.
This may also apply to other Aptio bioses as well as the Panasonic CF-U1, and if the machine isnt
bootable you may be able to use a cheap spi adapter to dump the bios, in the case of the CF-U1 it
uses an LPC flash which I don't think you can get cheap clips and readers for and its buried in the
machine so a nuisance to get to.
I got this encoded password 5B 8C B6 15 11 41 6C 59 C7 E5 22 53 7D 0E D8 5E 33 1B 8E 8D E9 87 44 16 9F 85 FA E1 55 12 B0 ED 0B 43 66 9E C1 78 1C 86 77 16 D2 A9 2D 3D 88 D0 E3 63 3E F7 99 8A F4 1D 4F B1 AA 44 05 D8 60 6B 5B A6 B6 41 11 FD 6C 05 C7 F8 22 DA 7D 8D D8 7D 33 EF 8E DF E9 97 44 39 9F 8E FA 7C 55 65 B0 35 0B FC 66 A1 C1 85 1C 92 77 16 D2 A9 2D 3D 88 D0 E3 63 3E F7 99 8A F4 1D 4F B1 AA 44 05 D8 60 6B . I did the xor of
5B 8C B6 15 11 41 6C 59 C7 E5 22 53 7D 0E D8 5E 33 1B 8E 8D E9 87 44 16 9F 85 FA E1 55 12 B0 ED 0B 43 66 9E C1 78 1C 86 77 16 D2 A9 2D 3D 88 D0 E3 63 3E F7 99 8A F4 1D 4F B1 AA 44 05 D8 60 6B
with
5B A6 B6 41 11 FD 6C 05 C7 F8 22 DA 7D 8D D8 7D 33 EF 8E DF E9 97 44 39 9F 8E FA 7C 55 65 B0 35 0B FC 66 A1 C1 85 1C 92 77 16 D2 A9 2D 3D 88 D0 E3 63 3E F7 99 8A F4 1D 4F B1 AA 44 05 D8 60 6B .
After xor I got this result 2a005400bc005c001d00890083002300f400520010002f000b009d007700d800bf003f00fd0014000000000000000000000000000000000000000000000000. Ignoring the 00 part 2a 54 bc 5c 1d 89 83 23 f4 52 10 2f 0b 9d 77 d8 bf 3f fd 14 this is my final one. Based on the tabel i could found this letters. Please let me know if this procedure is the right one to follow . Also if you could help me with the missing letters it would be very helpful.
2a is '
54
bc
5c
1d is 2
89
83
23 is f
f4
52
10 is z
2f is +
0b
9d
77
d8
bf
3f
fd
14 is b