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@geuis
Last active January 10, 2024 16:43
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Get Youtube video urls
// Run from the dev tools console of any Youtube video
// Accurate as of July 2, 2020.
//
// Copy and paste this into the dev console in a browser with the desired video loaded.
//
// NOTE: Some Youtube videos do not directly expose the video url in the response.
// This script doesn't currently attempt to handle those. It will work for most other general video types though.
(async () => {
const html = await fetch(window.location.href).then((resp) => resp.text()).then((text) => text);
const startStr = 'ytplayer.config = {';
const start = html.indexOf(startStr) + startStr.length - 1;
const end = html.indexOf('};', start) + 1;
const playerObj = JSON.parse(html.slice(start, end));
playerObj.args.player_response = JSON.parse(playerObj.args.player_response);
const videoUrls = playerObj.args.player_response.streamingData.adaptiveFormats.reduce((acc, item) => {
if (!acc[item.quality]) {
acc[item.quality] = {};
}
const mimeType = item.mimeType.split(';')[0];
acc[item.quality][mimeType] = item;
return acc;
}, {});
console.log('!!', videoUrls);
})();
@towfiqi
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towfiqi commented Feb 27, 2018

Doest work anymore in 2018

@Viktor19931
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ytplayer.config.args.url_encoded_fmt_stream_map doesnt work at mobile version of youtube.

@Viktor19931
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Does someone know how to get direct url on mobile version of youtube ?

@darkov19
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Uncaught TypeError: Cannot read property 'split' of undefined
at youtubedl.js:15

@geuis
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Author

geuis commented Jan 6, 2020

@ViralShastri review the updated script.

@nysander
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in what language is it written in? I need to rewrite it to swift

@geuis
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geuis commented Jan 20, 2020

@nysander its javascript.

@roffe
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roffe commented Feb 15, 2020

does not work on for example https://www.youtube.com/watch?v=IcrbM1l_BoI

VM780:13 Uncaught (in promise) TypeError: Cannot read property 'split' of undefined
at :13:6

@yair-man
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Where do I put this code?

@geuis
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geuis commented Mar 14, 2020

@yair-man its in the very first line

@Joshuajrodrigues
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Uncaught TypeError: Cannot read property 'split' of undefined
at :2:4

got this when i tired it out in console

@jarvis1234d
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Uncaught (in promise) TypeError: Cannot read property 'split' of undefined
It shows this error everytime I run it.
I get the url of the page when by using window.location.href but I need the url which contains other properties such as screen-resolution, frame-rate, bit-rate , etc.

I also tried using ifram api by using src="https://www.youtube.com/get_video_info?video_id={videoId}" but the file which it returns gives this error status=fail&errorcode=2&reason=Invalid+parameters..

Please help if you can.

@geuis
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geuis commented Jul 3, 2020

@Joshuajrodrigues @jarvis1234d script is now updated. Try it out.

@serjmac
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serjmac commented Aug 6, 2020

It works with the updated july 2nd script, thank you @geuis

however the url from every object only contains video stream. Is there a way to get the url for a full video+audio stream?

@realrecordzLab
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After running the script what's the field that hold the url? I suppose that is the one named signatureCypher ? It starts with "s=yy.." so how to extract the url?

@3Samourai
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For Download video with audio

(async () => {
  html = await fetch(window.location.href).then(resp => resp.text()).then(text => text);
  startStr = 'ytplayer.config = {';
  start = html.indexOf(startStr) + startStr.length - 1;
  end = html.indexOf('};', start) + 1;
  playerObj = JSON.parse(html.slice(start, end));
  playerObj.args.player_response = JSON.parse(playerObj.args.player_response);
  videoUrls = playerObj.args.player_response.streamingData.formats[1].url;
  videoUrls = videoUrls.replace('"', 'r');
  return console.log(videoUrls);
})();

@Christopher-CO
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For Download video with audio

(async () => {
  html = await fetch(window.location.href).then(resp => resp.text()).then(text => text);
  startStr = 'ytplayer.config = {';
  start = html.indexOf(startStr) + startStr.length - 1;
  end = html.indexOf('};', start) + 1;
  playerObj = JSON.parse(html.slice(start, end));
  playerObj.args.player_response = JSON.parse(playerObj.args.player_response);
  videoUrls = playerObj.args.player_response.streamingData.formats[1].url;
  videoUrls = videoUrls.replace('"', 'r');
  return console.log(videoUrls);
})();

Thank you, this works great!

@realrecordzLab
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realrecordzLab commented Nov 17, 2020

For Download video with audio

(async () => {
  html = await fetch(window.location.href).then(resp => resp.text()).then(text => text);
  startStr = 'ytplayer.config = {';
  start = html.indexOf(startStr) + startStr.length - 1;
  end = html.indexOf('};', start) + 1;
  playerObj = JSON.parse(html.slice(start, end));
  playerObj.args.player_response = JSON.parse(playerObj.args.player_response);
  videoUrls = playerObj.args.player_response.streamingData.formats[1].url;
  videoUrls = videoUrls.replace('"', 'r');
  return console.log(videoUrls);
})();

Thank you, this works great!

I've tried the script but I get a reject in promise. Seems not working. TypeError: Cannot read property 'url' of undefined↵ at <anonymous>:8:71

@tcarroll2
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in what language is it written in? I need to rewrite it to swift

@nysander - did you ever get this converted to Swift?

@nysander
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in what language is it written in? I need to rewrite it to swift

@nysander - did you ever get this converted to Swift?

Nope because Apple is very strict with playback rights and I have dropped idea of this script in my app

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