FizzBuzz JavaScript solution

FizzBuzz.js

for (var i=1; i <= 20; i++)
{
    if (i % 15 == 0)
        console.log("FizzBuzz");
    else if (i % 3 == 0)
        console.log("Fizz");
    else if (i % 5 == 0)
        console.log("Buzz");
    else
        console.log(i);
}

function fizzBuzz(n) {
for(let i=1; i<=n; i++)
{

if((i%3==0) && (i%5==0))
{
console.log("FizzBuzz");
}

if((i%3==0) && (i%5!==0))
{
console.log("Fizz");
}

if((i%5==0) && (i%3!==0))
{
console.log("Buzz");
}

if((i%3!==0) && (i%5!==0))
{
console.log(i);
}

}

}

const fizzBuzz = n => (n%15? (n%3? (n%5? (n%7? '' : 'woff') :'buzz') : 'fizz') : 'fizzbuzz') || n;

public class Solution {

public static void main(String[] args) throws IOException {
    int n = 0;
    
    for (int i = 1; i <= n; i++){
        if(i % 3 == 0 && i % 5 == 0)
        System.out.println("FizzBuzz");
    else if (i % 3 == 0 && i % 5 != 0)
        System.out.println("Fizz");
    else if (i % 5 == 0 && i % 3 != 0)
        System.out.println("Buzz");
    else
        System.out.println(i);  
    }
}

}

function fizzBuzz(arr){
let len = arr.length;
for(let i = 0; i < len; i++){
//multiples of 3 and 5
if(arr[i] % 3 === 0 && arr[i] % 5 === 0){
arr[i] = "FizzBuzz";
}
//multiples of 3 but not multiples of 5
if(arr[i] % 3 === 0 && arr[i] % 5 !== 0){
arr[i] = "Fizz";
}
//multiples of 5 but not multiples of 3
if(arr[i] % 3 !== 0 && arr[i] % 5 === 0){
arr[i] = "Buzz";
}
}
return arr;
}

//call the function torender result.
console.log(fizzBuzz([1, 2, 3,4,5,6,7,8,9,10,11,12,13,14,15]))

Switch Case Solution
`

for (var i = 1; i <= 100; i++) {
switch (true) {
case i % 5 == 0 && i % 3 == 0:
console.log("FizzBuzz");
break;
case i % 5 == 0 && i % 3 != 0:
console.log("Buzz");
break;
case i % 3 == 0 && i % 5 != 0:
console.log("Fizz");
break;
default:
console.log(i);
break;
}
}`

for (num = 1; num < 101; num++) {
resultado = "";
if (num % 3 === 0) {
resultado = "Fizz";
}
if (num % 5 === 0) {
resultado = resultado + "Buzz";
}
if (resultado === "") {
resultado = num;
};
console.log(resultado);
};

omo..!!!....HEADache don dey worry me...

for (let i=1; i <=100; i++){
   if(i  %  3 === 0  && 1 % 5 === 0){
    console.log('FizzBuzz')
  }else if(i  %  3 === 0){
    console.log('Fizz')
  }else if(i % 5 == 0){
    console.log('Buzz')
  }else{
   console.log(i)
  }
}

short modern js solution

function fizzBuzz(n){
     for(let i = 0 ; i < n ; ){
            console.log( 
                   (++i % 3 ? "" : "fizz") + (i % 5 ? "" : "buzz") || i
                      )
       }
}

using short synthax is fun and games until you want to read the code.

short modern js solution

function fizzBuzz(n){
     for(let i = 0 ; i < n ; ){
            console.log( 
                   (++i % 3 ? "" : "fizz") + (i % 5 ? "" : "buzz") || i
                      )
       }
}

using short synthax is fun and games until you want to read the code.

We're all here for fun and games, none of this is production code bruh

We're all here for fun and games, none of this is production code bruh

Agreed. If you need to adopt FizzBuzz for production use, you are in the wrong place. FizzBuzz enterprise edition is recommended for these use cases https://github.com/EnterpriseQualityCoding/FizzBuzzEnterpriseEdition

let i = 1;
while(i <= 100) {
console.log((${i%3===0?'Fizz':''}${i%5===0?'Buzz':''}) || i)
i++;
}``

Using currying is highly technical but for some reason, I think is not more reliable than one-line code (It divides so many fn to solved). I just think we can use HOC or using closures to limit the context.

If you want fun and games:

new Array(100)
    .fill()
    .map((_,i) => `${i%3===0?'Fizz':''}${i%5===0?'Buzz':''}`)
    .forEach(console.log)

or a little more testable

const fizzbuzz = (_,i) => `${i%3===0?'Fizz':''}${i%5===0?'Buzz':''}`

new Array(10).fill().map(fizzbuzz).forEach(console.log)

@essenmitsosse

The use of forEach is not necessary here since map already traverses the array.
But I like how you used fill

new Array(100).fill().forEach((_,i) => {
    i++
    console.log((`${i%3===0?'Fizz':''}${i%5===0?'Buzz':''}`) || i)
})

@Megafry If you want fizzbuzz to be side-effect free, it still makes sense to separate the two. Also, I usually wouldn't expect map to have a side effect — that's what forEach is for. It is an additional traversal, but in most cases, the gain in clarity should outweigh the performance hit.

Not the smallest / most elegant solution but when that pesky product manager wants to add "boop" on 7 it won't require a refactor

const fizzBuzz = (duration = 100) => Array(duration).fill().map((_, i) => {
  i++
  const subs = new Map([[15, "Fizzbuzz"], [3, "Fizz"], [5, "Buzz"] ])
  const match = Array.from(subs.keys()).find(k => i % k === 0)
  return match ? `${subs.get(match)}` : `${i}`;
})

console.log(fizzBuzz())

for (var i = 1; i <= 100; i++) {
switch (true) {
case i % 5 == 0 && i % 3 == 0:
console.log("FizzBuzz");
break;
case i % 5 == 0 && i % 3 != 0:
console.log("Buzz");
break;
case i % 3 == 0 && i % 5 != 0:
console.log("Fizz");
break;
default:
console.log(i);
break;
}
}

Thanks man, was looking for switch case implementation on this one.

for (let i = 1; i <= 100; i++) {
  const fizz = i % 3 === 0 ? "Fizz" : ""
  const buzz = i % 5 === 0 ? "Buzz" : ""
  console.log(`${fizz}${buzz}` || i)
}

const fizzBuzz = (num, rules) => {
  const result = [];
  for (let i = 1; i <= num; i++) {
    result.push(applyRules(i, rules));
  }
  return result;
};

const applyRules = (num, rules) => {
  const output = rules.reduce((result, rule) => {
    if (rule.condition(num)) {
      result += rule.output;
    }
    return result;
  }, '');

  return output || num;
};
 // Example usage:
  const isMultipleOf = (n) => (num) => num % n === 0;
  const rules = [
    { condition: isMultipleOf(3), output: 'Fizz' },
    { condition: isMultipleOf(5), output: 'Buzz' },
  ];
    const resultArray = fizzBuzz(15, rules);
    console.log(resultArray);

//para imprimir en la página web const n= window.prompt("Ingrese un número: "); for(i=1; i<=n; i++) if(i%3==0 && i%5==0){ console.log("FizzBuzz\n"); } else if(i%3==0 && i%5!=0){ console.log("Fizz\n"); } else if(i%3!=0 && i%5==0){ console.log("Buzz\n"); } else{ console.log(i\n); }